WAP TO ACCEPT STRING AND COUNT A COMES N TIMES B COMES N TIMES C COMES N TIMES

WAP TO ACCEPT STRING AND COUNT A COMES N TIMES B COMES N
TIMES C COMES N TIMES D COMES N TIMES AND SO ON.........
AT LAST UNTIL Z COMES N TIMES...............

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WAP TO ACCEPT STRING AND COUNT A COMES N TIMES B COMES N TIMES C COMES N TIMES D COMES N TIMES AN..

Answer / vignesh1988i

this logic is for 'A'(capital) to 'z'(small)......

#include<stdio.h>
#include<conio.h>
void main()
{
int count;
char str[100];
printf("enter the string :");
gets(str);
for(int i=65;i<=122;i++)
{
count =0;
for(int j=0;str[j]!='\0';j++)
{
if(str[j]==i)
count++;
}
printf("the character %c occurs %d times \n",i,count);
}
getch();
}

thank you

Is This Answer Correct ?

5 Yes

2 No

WAP TO ACCEPT STRING AND COUNT A COMES N TIMES B COMES N TIMES C COMES N TIMES D COMES N TIMES AN..

Answer / vignesh1988i

m minor modification

#include<stdio.h>
#include<conio.h>
void main()
{
int count;
char str[100];
printf("enter the string :");
gets(str);
for(int i=65;i<=122;i++)
{
count =0;
for(int j=0;str[j]!='\0';j++)
{
if(str[j]==(char)i)
{
printf("the character %c occurs %d times \n",i,count);

count++;
}
}
}
getch();
}

thank you

Is This Answer Correct ?

2 Yes

0 No

WAP TO ACCEPT STRING AND COUNT A COMES N TIMES B COMES N TIMES C COMES N TIMES D COMES N TIMES AN..

Answer / priyanka

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,count;
char str[100];
clrscr();
printf("enter the string :");
gets(str);
for(i=65;i<=122;i++)
{
count =1;
for(j=0;str[j]!='\0';j++)
{
if(str[j]==i)
count++;
}
printf("the character %c occurs %d times \n",i,count);
}
getch();
}

Is This Answer Correct ?

2 Yes

0 No

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