Write a C program that defines a 2-dimentional integer array called A [50][50].

Write a C program that defines a 2-dimentional integer array
called A [50][50]. Then the elements of this array should
randomly be initialized either to 1 or 0. The program should
then print out all the elements in the diagonal (i.e.
a[0][0], a[1][1],a[2][2], a[3][3], ……..a[49][49]). Finally,
print out how many zeros and ones in the diagonal.

Question Posted / cfuzz

3 Answers
4985 Views
Infosys, I also Faced
E-Mail Answers

Answers were Sorted based on User's Feedback

Write a C program that defines a 2-dimentional integer array called A [50][50]. Then the elements o..

Answer / senthil

// correcting Cfuzz answer

#include <stdio.h>
#include <stdlib.h> // for rand function

#define ROWS 50
#define COLS 50

int main(void)
{
int A[ROWS][COLS];
int i=0, j=0;
int zero_cnt = 0;
int one_cnt = 0;

/* Initializing*/
for(i=0; i < ROWS; i++) {
for(j=0; j < COLS; j++) {
A[i][j] = rand() % 2;
}
}

// here one loop is sufficient
for(i=0; i < ROWS; i++) {
printf("A[%d][%d] = %2d\n", i, i, A[i][i]);
if(A[i][i] == 0)
{
zero_cnt++;
}
else //if(A[i][i] == 1)
{
one_cnt++;
}
}
printf("\nNumber of zeros in the diagonal = %d", zero_cnt);
printf("\nNumber of ones in the diagonal = %d", one_cnt);
}

Is This Answer Correct ?

0 Yes

0 No

Write a C program that defines a 2-dimentional integer array called A [50][50]. Then the elements o..

Answer / pushpender singh

#include<stdio.h>

main
{
int a,b,c;
a[50][50];
b[][];
for(c=0;c>50;c+a)
{
a=a+c;
b=a;
}
printf("%d",b[][]);
}
}

Is This Answer Correct ?

0 Yes

2 No

Write a C program that defines a 2-dimentional integer array called A [50][50]. Then the elements o..

Answer / cfuzz

/* THIS CODE IS WRONG...CUZ I CAN'T COUNT ZEROS*/

#include <stdio.h>

#define ROWS 50
#define COLS 50

int count_occur(int A[], int num_elements, int value);

int main(void)
{
int A[ROWS][COLS];
int i=0, j=0;
int num_occ, value=0;

/* Initializing*/

for(i=0; i < ROWS; i++) {
for(j=0; j < COLS; j++) {
A[i][j] = 0;
A[i][j] = 1;
A[i][j] = rand() % 2;

}
}

for(i=0; i < ROWS; i++) {
for(j=0; j < COLS; j++) {

if (i == j){
printf("%2d", A[i][j]);
}
}

}

for(value=0; value<1; value++)
{

num_occ = count_occur(A, 50, value);

if (value = 1){

printf("\n\nThe value %d was found %d times.\n", value,
num_occ);
}

else if (value = 0){

printf("\n\nThe value %d was found %d times.\n", value,
num_occ);
}

}

}

int count_occur(int A[], int num_elements, int value)
/* checks array a for number of occurrances of value */
{
int i, count=0;
for (i=0; i<num_elements; i++)
{
if (A[i] == value)
{
++count; /* it was found */
}
}
return(count);
}

Is This Answer Correct ?

0 Yes

3 No

Post New Answer