Answer / manoj

select employee_id, count(*) from employees group by
employee_id having count(*) > 1

Answer / avik ganguly

select * from emp a where rowid = (select max(rowid) from
emp where empno = a.empno group by empno having count(*) >1)

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1. Using the XML Document below, with the URI “recipe.xml” define the following queries in XQuery: a.) Give the names of all breakfast in the menu. b.) Select breakfasts that have price lower than $7.00? <?xml version="1.0"?> <breakfast_menu> <food> <name>Belgian Waffles</name> <price>$5.95</price> <description> two of our famous Belgian Waffles with plenty of real maple syrup </description> <calories>650</calories> </food> <food> <name>Strawberry Belgian Waffles</name> <price>$7.95</price> <description> light Belgian waffles covered with strawberries and whipped cream </description> <calories>900</calories> </food> <food> <name>Berry-Berry Belgian Waffles</name> <price>$8.95</price> <description> light Belgian waffles covered with an assortment of fresh berries and whipped cream </description> <calories>900</calories> </food> <food> <name>French Toast</name> <price>$4.50</price> <description> thick slices made from our homemade sourdough bread </description> <calories>600</calories> </food> <food> <name>Homestyle Breakfast</name> <price>$6.95</price> <description> two eggs, bacon or sausage, toast, and our ever-popular hash browns </description> <calories>950</calories> </food> </breakfast_menu>

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Can you have a nested transaction?

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how will I find the duplicate rows count from employees tablein oracle.

2 Answers  

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