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Could someone answer the following testing Questions?
1)Give 5 reasons why a build can be released with bug
2)Write a bug report for a word processor program which
crashes when the
contents of 89th column is been sorted in assending order.
3)write test 10 cases for program which has a table with 2
fields of NAME
od char type and CLASS of INT type.NAME fields is truncated
after 26
charaters and CLASS takes value between 1 to 9 both included.
There are 3 possible opearations program can perform
a)When a new student joins the class the program adds a new
field
b)When student leaves the class the field get deleted
c)when student gets promoted then program incremts the class
by 1
Write 5 test cases for the scenario.
4)write 10 test cases for a program that takes date in
dd/mm/yyyy format
and prints it out with a increment of 1.
for dates (dd) can be given in the range 1<=dd>=30
for months (mm) can be given in the range 1<=mm>=12
for years(yyyy) can be given in the range 1600<=yyyy>=9999
5)Give 5 bugs that could cause a program to crash when it
printed the
999999 th pages 1000001th line.
- 6 Answers
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Answer / kapil
Build can be released with bug only with the following
scenarios.
1 Bug severity is not effecting the functionality of
product.
2 Test team has got the update that in the next build this
bug will be fixed.
3 Time constraint.
| Is This Answer Correct ? | 35 Yes | 0 No |
Answer / sandeep garg
1)
a) Bug is of low severity and an alternate is available.
b) The module containing bug is isolated from the intended
users.
c) Bug is not on priority for the BAs to be resolved in
that release cycle.
d) Bug is cosmetic and of low priority.
e) Time constraing unless the bug is a major OR critical
one.
2)
Application: Word processor program i.e. WPP
Severty: Critical
Priority: Major
Platform: Microsoft XP (SP 3)
Reproducibility: Everytime
Issue: WPP which crashes when the contents of 89th column
is been sorted in assending order.
Steps to Reproduce:
1. Start WPP
2. Add 100 columns
3. Add 2 rows
4. Add data in rows
5. Apply Ascending filter on row 89th by navigating Data
tab > Filter
6. Click on Filter icon button on 89th column
7. Once data in the colmn is arranged in Descending order,
again click on Filter icon button on 89th column to have
data in ascending order
Instead of re arranding data, WPP crashes.
3)
1. Try to add a student for 15 for class 1-9, it should be
added.
2. Try to add a student for 0 character for class 1-9, It
should not be saved as name is required.
3. Try to add a student for 27 character for class 1-9 and
validate truncation of name upto 26th character.
4. Try to add a student for 1 character for class 1-9, It
should be added
5. Try to add a student for 26 character for class 1-9, It
should be added
6. Try to add a student for 1-26 characterm for class 0, It
should not be added
7. Try to add a student for 1-26 character for class 1, It
should be added.
8. Try to add a student for 1-26 character for class 5, It
should be added.
9. Try to add a student for 1-26 character for class 9, It
should be added.
10. Try to add a student for 1-26 character for class 10,
It should NOT be added as there is no class 10th.
Duplicacy:
While saving duplicate data for same class, system should
alert user to save the name in a different format? But
since it is character type only. how would we do that? May
be DOB, Mother's maiden name
Student leave the program
11. Validate that student Name field Against the Class 1-9.
Removing duplicate data? System should alert by giving
details like Father Name, DOB, Mother's maiden name to
confirm deletion
12. Student gets promotion....
1. Class 1-8 gets promotion: Validate if class is
incremented by 1.
2. Class 1-8 gets promotion: Student name is entered
against incremented class.
3. Class 1-8 gets promotion: Name is deleted from previous
class for the student who is just promoted.
4. Class 9 student gets promotion: Validate if student Name
is deleted from class 9 who is just promoted.
4)
ddmmyy Boundry value Analysis Negative
0/0/1599 > Not Allwoed
0/0/10000 > Not Allwoed
0/0/1700 > Not Allwoed
0/1/1700> Not Allwoed
31/1/1700 > Not Allowed
1/0/1700 > Not Allwed
30/13/1700 > Not Allowed
31/13/1700 > Not Allwoed
0/12/1700 > Not Allowed
30/12/1700 > Allowed and validate if it prints in 31/12/1700
30/10/1599 > Not Allowed
30/10/10000 > Not Allowed
| Is This Answer Correct ? | 21 Yes | 8 No |
Answer / manika
These are still the latest questions for adobe test in 2010
november!!!
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / akhil
0/0/1599 > Not Allwoed
0/0/10000 > Not Allwoed
0/0/1700 > Not Allwoed
0/1/1700> Not Allwoed
31/1/1700 > Not Allowed
1/0/1700 > Not Allwed
30/13/1700 > Not Allowed
31/13/1700 > Not Allwoed
0/12/1700 > Not Allowed
30/12/1700 > Allowed and validate if it prints in 31/12/1700
30/10/1599 > Not Allowed
30/10/10000 > Not Allowed
| Is This Answer Correct ? | 1 Yes | 3 No |
Answer / tarun
Hi,
I am aware of these questions thanks for posting and these
are very helpful , one query can anybody post latest
question asked in August 2009 in Adobe
Thankful to all!!!!!
satijaa.tarun@gmail.com
Regards
Tarun
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / shailaja
1)Give 5 reasons why a build can be released with bug
A:The build is not released with bugs.To know whether the
application is working according to requirements the build
is tested.but intentionally the build is not released with
bugs.
reasons may be:
1.poor requirements
2.developers may not have preior experience
3.mis communication between the team
4.changing requirements
5.time pressure
6.software complexity
| Is This Answer Correct ? | 8 Yes | 29 No |
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