Answer / abdur rab

#include <stdio.h>

char* str_str ( char* cp_str, char* cp_pattern )
{
char* cp_temp = NULL;
int n_pattern_length = 0;

n_pattern_length = strlen ( cp_pattern );

while ( cp_str && *cp_str ) {
if ( !strncmp ( cp_str, cp_pattern, (
n_pattern_length ) ) ) {
cp_temp = cp_str;
break;
}
else cp_str++;
}

return ( cp_temp );

}

int main ( int argc, char* argv [ ] )
{
char array [] = {"Hello World"};
char* cp_temp = NULL;

cp_temp = str_str ( array, "lo " );
if ( NULL != cp_temp ) {
printf ("\n%s", cp_temp);
} else printf ("\nReturned null");

return ( 0 );

}

The code is::::: if(condition) Printf("Hello"); Else Printf("World"); What will be the condition in if in such a way that both Hello and world are printed in a single attempt?????? Single Attempt in the sense... It must first print "Hello" and it Must go to else part and print "World"..... No loops, Recursion are allowed........................

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