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I wish to understand How to subnet a class c address
I understand the principle of subnetting as 192.168.5.0 /24
1st Subnet > 192.168.5.1 Last address > 192.168.5.126
192.168.5.127 is Broadcast address
2nd Subnet > 192.168.5.128 last address > 192.168.5.254
Even the division into 4 Subnets , i Know the formula but
still am having to understand HOW TO CONFIGURE ON THE TCP/IP
CONFIGURATION LOCAL AREA NETWORK HOW TO PUT THE SUBNET WHERE
TO PUT THE SUBNET
Am studying the Network + Afterwards The MCSE , CCNA ,CCNP
I got a scenario > 260 hosts , DHCP , DNS , 1 GATEWAY ,1
wireless access point on the Network address 192.168.2.0 /24
to document the IP Scheme & Configure afterwards
PLease do me a favour to explaine me how to handle this , I
have been through e -books , sites of Techtutorial and so on
but nobody gives the explanations of how to do it , How to
nanage the configuration .
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Answer / bhavin jani
Your Question is little bit confused, but let me tell me on
this from my side
1. You can configure subnet in two way, Super-sub
netting & Class full address rite
2. You should now the decibel notation for 8 bit
subnet,16 bit or 24 bite subnet
3. There is some rule in decibel notation subject
applied to Sub netting, A. there should not be all 0(Zero)
in Host Address B. there should not be all 1(One) in host
address rite this are all broadcasting address
4. Your IP is 192.168.5.0/24 so you need to know
decibel code behind that
5. For Eg 128,64,32,16,8,4,2,1 is simple code to
calculate dec
6. 192.168.41.5.0 = 192 =128+64 (Dec not :-
11000000).168 =128+32+8 (dec not 10101000).5 = 4+1(Dec
No :- 00000101)
It is to huge if you get to understand the basic of Network
of this Sub netting you can design & Configure Number of
Network
| Is This Answer Correct ? | 6 Yes | 2 No |
Answer / todd
I dont think that you can do it classfully. It should use
classless subnetting. learn the basics first.
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / abhishek
Look , ill give u an easy tutorial. This goes well for all
classes, A, B and C.
Example -- Read Carefully
IP address = 192.168.5.110
Subnet Mask = 255.255.255.192 = /26 (CIDR notation)
Let a = Number of "1" bits in fourth octet in subnet mask = 2
Let b = Number of "0" bits in fourth octet in subnet mask = 6
Number of Subnets = 2^a = 2^2 = 4
Number of hosts / subnet = 2^b - 2 = 2^6 - 2 = 32 - 2 = 30
Block Size = 256 -192 = 64 (Subnet Spacing)
Let 192.168.5 = x
Row1 = x.0 x.64 x.128 x.192
Row2 = x.1 x.65 x.129 x.193
Row3 = x.62 x.126 x.190 x.254
Row4 = x.63 x.127 x.191 x.255
Row1 denotes the subnet address.
Row4 denotes broadcast address for each subnet.
Row2 to Row3 are the range of hosts for the respective subnets.
So ip address 192.168.5.110 lies in subnet 192.168.5.64
whose broadcast address is 192.168.5.127.
Hope it helps!!!!
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / richard phillips
hello i am new to this, i need to know how will i complete
a basic scenario that ask the required number of networks
that is 80 and the minimum number of host that is 3000 and
the network address is 10.0.0.0 and i need to need how to
compute to get the answer on what is the subnet mask.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / amar pratap
if ur question is right just use subnetting on one bit
like192.168.5.x/25.and u have ur first subnet as
192.168.5.126,last address 192.168.5.126, broadcast address
192.168.5.127..its easy.....keep practice on subnetting....
| Is This Answer Correct ? | 1 Yes | 3 No |
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