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I wish to understand How to subnet a class c address
I understand the principle of subnetting as 192.168.5.0 /24
1st Subnet > 192.168.5.1 Last address > 192.168.5.126
192.168.5.127 is Broadcast address
2nd Subnet > 192.168.5.128 last address > 192.168.5.254
Even the division into 4 Subnets , i Know the formula but
still am having to understand HOW TO CONFIGURE ON THE TCP/IP
CONFIGURATION LOCAL AREA NETWORK HOW TO PUT THE SUBNET WHERE
TO PUT THE SUBNET
Am studying the Network + Afterwards The MCSE , CCNA ,CCNP
I got a scenario > 260 hosts , DHCP , DNS , 1 GATEWAY ,1
wireless access point on the Network address 192.168.2.0 /24
to document the IP Scheme & Configure afterwards
PLease do me a favour to explaine me how to handle this , I
have been through e -books , sites of Techtutorial and so on
but nobody gives the explanations of how to do it , How to
nanage the configuration .
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Answer Posted / abhishek
Look , ill give u an easy tutorial. This goes well for all
classes, A, B and C.
Example -- Read Carefully
IP address = 192.168.5.110
Subnet Mask = 255.255.255.192 = /26 (CIDR notation)
Let a = Number of "1" bits in fourth octet in subnet mask = 2
Let b = Number of "0" bits in fourth octet in subnet mask = 6
Number of Subnets = 2^a = 2^2 = 4
Number of hosts / subnet = 2^b - 2 = 2^6 - 2 = 32 - 2 = 30
Block Size = 256 -192 = 64 (Subnet Spacing)
Let 192.168.5 = x
Row1 = x.0 x.64 x.128 x.192
Row2 = x.1 x.65 x.129 x.193
Row3 = x.62 x.126 x.190 x.254
Row4 = x.63 x.127 x.191 x.255
Row1 denotes the subnet address.
Row4 denotes broadcast address for each subnet.
Row2 to Row3 are the range of hosts for the respective subnets.
So ip address 192.168.5.110 lies in subnet 192.168.5.64
whose broadcast address is 192.168.5.127.
Hope it helps!!!!
| Is This Answer Correct ? | 3 Yes | 1 No |
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