void main() { for(int i=0;i<5;i++); printf("%d",i); } What i

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void main()
{
for(int i=0;i<5;i++);
printf("%d",i);
}

What is the output?..

Question Posted / mariaalex007

32 Answers
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void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / vera

012345
not
0
1
2
3
4
cz their is no printf("\n");
first time i=0 it print 0
scnd time i=1 it print 1
last time i=4 it print 4
but not 5 cz when i=5 :i is not <5
so it will not print 5
10x

Is This Answer Correct ?

4 Yes

5 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / ghiga

0 1 2 3 4 5

Is This Answer Correct ?

2 Yes

3 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / sanjeevi

Guys remember things
1) we cant declare loop variable inside for
2) here i is local to for loop alone..

Is This Answer Correct ?

1 Yes

2 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / chuimaya

It gives an error coz we cannot declare a variable inside the for loop.

Is This Answer Correct ?

0 Yes

1 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / krishna krish

0 1 2 3 4

Is This Answer Correct ?

6 Yes

7 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / avi

Error will occur

Is This Answer Correct ?

2 Yes

3 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / ttt

0
1
2
3
4

Is This Answer Correct ?

1 Yes

2 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / ramveer

for the first loop i is 0 so 0 is printed
for 2nd time i++ i becomes 1 so 1 is printed
for 3rd time i becomes 2 so 2 gets printed
for 4th time i becomes 3 so it gets prited
for 5th time i becomes 4 so it gets printed
now for this time i has became 5 and this isn't in loop boudary as the condition is i<5 so its breaks out of loop.

so the ans is "0 1 2 3 4" .

Is This Answer Correct ?

9 Yes

10 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / erdem

Ofcourse

01234

(logic for start from 0 to 4 and no blank or tab)

Is This Answer Correct ?

1 Yes

2 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / sansiri

the answer is...........0

because in c,c++ program when the semicolon is present then it is considered as one statement
here for loop has a semicolon so it consider one statement and execute only one so that the initial value o is printed

Is This Answer Correct ?

0 Yes

1 No

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