Answer / elumalai.k

select id,max(salary)from employee where salary<(select
max(salary)from employee)

Answer / ashish

hey u can try This It defenately work...It for The nth
position mean for the N th node try it out.......



SELECT *
FROM emp A
WHERE (n-1) = (
SELECT COUNT(DISTINCT(B.salary))
FROM emp B
WHERE B.salary > A.salary)

Answer / elumalai.k

select top1 id,salary from employee
where
(salary<(select max (salary) As sal from employee As Empp))
orderby salary desc.

Answer / kavitha

select * from emp as a

where sal < 2 from emp as a1
on
(
a.idno=a1.idno
)

Answer / lekhrajdeshmukh

select top 1 id,salary from(select top 2 id,salary from
employee group by id,salary order by salary desc)a order by
salary asc

Answer / sivanandam

SELECT ID,MAX(SALARY) FROM EMP
WHERE SALARY < SELECT MAX(SALARY) FROM EMP

Answer / bobby

SELECT sm ,custid ,ordyear,amount FROM
(SELECT sm ,custid ,ordyear,amount,Rank() OVER (ORDER BY
amount desc)as Rank
FROM dbo.OrderCust)p where rank=2


This is used to select all the rows having the second max
salary.

Answer / tusar

select distinct (a.sal),empno from emp a
where &N = (select count (distinct(b.sal))
from emp b where a.sal <= b.sal);

Answer / chan

SELECT ID, SALARY FROM
(
SELECT ID, SALARY, ROW_NUMBER() OVER (ORDER BY SALARY) AS RN
FROM EMPLOYEE
)
WHERE RN = 1

(YOU CAN CHANGE VALUE OF RN = ANY NUMBER AND YOU WILL GET
THAT VALUE)

Answer / deepa

drop table #temp
select top 2 identity(int,1,1) as SlNo, *
into #temp from employee order by salary desc
select * from #temp where SlNo = 2

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