int i = 1;
int j = 1;
System.Console.WriteLine(i == j);
System.Console.WriteLine(i.ToString() == j.ToString());
System.Console.WriteLine((object)i == (object)j);
Give the sample code above, what is the output to the console?

Answers were Sorted based on User's Feedback



int i = 1; int j = 1; System.Console.WriteLine(i == j); System.Console.WriteLine(i.ToString() == ..

Answer / aspdev556

true
true
false

Is This Answer Correct ?    43 Yes 6 No

int i = 1; int j = 1; System.Console.WriteLine(i == j); System.Console.WriteLine(i.ToString() == ..

Answer / sahdev singh

True - First time we are comparing only values.
True - Second time also we are comparing only values.
False - We are comparing reference of two objects.

Is This Answer Correct ?    9 Yes 3 No

int i = 1; int j = 1; System.Console.WriteLine(i == j); System.Console.WriteLine(i.ToString() == ..

Answer / pp

provide the answer please

Is This Answer Correct ?    6 Yes 2 No

int i = 1; int j = 1; System.Console.WriteLine(i == j); System.Console.WriteLine(i.ToString() == ..

Answer / sasi

static void Main(string[] args)
{
int i = 1, j = 1;
Console.WriteLine(i + j);
Console.WriteLine("\n" + i.ToString() + j.ToString());
Console.WriteLine("\n"+((object)i==(object)j));
Console.ReadLine();
}
output:-
2
11
false

Is This Answer Correct ?    4 Yes 1 No

int i = 1; int j = 1; System.Console.WriteLine(i == j); System.Console.WriteLine(i.ToString() == ..

Answer / manoj yadav

1.TRUE... here we only comparing two value. if it is true.
then it wil execute (1==1).
2. TRUE.. here first we convert the int value in to string.
as bothe value are same so converted value wl also same
string so
3. WRONG..here we first give a reference to object. as
bothe objects reference cant be same so FALSE

Is This Answer Correct ?    3 Yes 0 No

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