Write a C function to search a number in the given list of
numbers. donot use printf and scanf
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Answer / vignesh1988i
#include<stdio.h>
#include<conio.h>
void main()
{
char a[]="enter the no. of terms tou are going to enter :";
char a1[100];
char n;
puts(a);
int flag=0;
n=getchar();
int n1;
n1=(int)n /* type casting*/
for(int i=0;i<n1;i++)
{
a[i]=getchar();
}
char a3[]="enter the number do you want to find :";
puts(a3);
char s;
s=getchar();
int b=(int)s;
for(i=0;i<n1;i++)
{
if(b==(int)a[i])
flag=1;
}
if(flag==1)
printf("number is found");
else
printf("not found");
getch();
}
this was the logic suddenly striked me.......................
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / abdur rab
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
int main ( int argc, char* argv[] )
{
int array [ 10 ] = { 546, 541, 128, 1027, 1000,
10234, 657, 343, 111, 272 };
char _variable [ 50 ];
int _count = 0;
int _value = 0;
memset ( _variable, '\0', 50 );
puts ("Enter the number to search: ");
gets ( _variable );
_value = atoi ( _variable );
for ( _count = 0; _count < 10; _count++ ) {
if ( array [ _count ] == _value ) {
puts ("Search SUCCESSFUL");
return ( 0 );
}
}
puts ("Search NOT SUCCESSFUL");
return ( 1 );
}
If u guys really want to check the given input is numeric,
use isnumeric function defined in ctypes.h
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / gg
Dear... Vignesh... r u tested?
if tested..., on what Compiler...
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / vignesh1988i
ya..... sorry... it wont work... since getchar gets only one
character the time.... when we give 48... i will take 4 and
8 .. but not as 48.... sorry for posting it... a lesson i
have learnt
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / abdur
sorry for the wrong information use isdigit(char)
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / vignesh1988i
very sorry yaar/.... i forgettenly used printf statements in
my before posts.......... i think this can be the logic...
if am not wrong..............
#include<stdio.h>
#include<conio.h>
void main()
{
char a[]="enter the no. of terms tou are going to enter :";
char a1[100];
char n;
puts(a);
int flag=0;
n=getchar();
int n1;
n1=(int)n /* type casting*/
for(int i=0;i<n1;i++)
{
a[i]=getchar();
}
char a3[]="enter the number do you want to find :";
puts(a3);
char s;
s=getchar();
int b=(int)s;
for(i=0;i<n1;i++)
{
if(b==(int)a[i])
flag=1;
}
if(flag==1)
{
char q[]="number is found";
puts(q);
}
else
{
char w[]="number not found";
puts(w);
}
getch();
}
| Is This Answer Correct ? | 2 Yes | 2 No |
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C 
