Answer / boni ravi

#include<stdio.h>
#include<conio.h>
main()
{
int i,n;
int x=0;
clrscr();
printf("enter n value");
scanf("%d",&n);
for(i=1;i<=n;i=i+2)
{
x=i+x;
}
printf("output is%d",x);
}

Answer / naresh m

main()
{
int sum=0,i;
int p,n;
printf("enter value for n");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
p=(i*2-1);
sum=sum+p;
}
printf("sum is %d",sum);
}

what will be the result of the following program ? char *gxxx() { static char xxx[1024]; return xxx; } main() { char *g="string"; strcpy(gxxx(),g); g = gxxx(); strcpy(g,"oldstring"); printf("The string is : %s",gxxx()); } a) The string is : string b) The string is :Oldstring c) Run time error/Core dump d) Syntax error during compilation e) None of these

2 Answers   IBM,

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