Answer / sha

let q=20,r=10 and p be a node previous to q
sequence is p-q-r
temp is pointer of link list.
then
temp=p->next;
p->next=temp->next;
p->next->next=temp;
and temp next can be conected to p->next->next->next if
there is any

Answer / pavny

Suppose List contains 3 no. 10, 20, 30
try to exchange 10 and 20.
head points to 10.

temp = head;
head = head -> next;
temp -> next = head - next;
head -> next = temp;

I think it works..

Answer / siva

head points 20
head=head->link;
link->next;
link->head=head->next

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