Answer / jigar

#include<stdio.h>
#include<conio.h>
void main()
{
int a,n,f;
clrscr();
for(n=1;n<=100;n++)
{
f=0;

for(a=2;a<n;a++)
{
if(n%a==0)
{
f=1;
break;
}
}
if(f==0)
printf("%d",n);
}
getch();
}
// JIGAR SHOBHANA (ANIDA VACHHARA-GONDAL)

Answer / anshul

#include <stdio.h>
#include<conio.h>

void main()
{
int i,j,k;
for (i=1;i<=100;i++)
{
k=0;
for (j=1;j<i;j++)
{
if (i%j==0)
{
k++;
}
}
if(k==2)
{
printf("%d \n",i);
}
}
getch();
}
It displays all prime no. from 1 to 100
commants: er.anshul2009@gmail.com

Answer / sureshbobra

#include<stdio.h>
#include<conio.h>
main()
{
int flag,i,j;
clrscr();
for(i=1;i<=100;i++)
{
flag=0;
for(j=2;j<=i;j++)
{
if(i%j==0)
{
flag++;
}
}
if(flag==1)
printf("%d\t",i);
}
getch();
}

Answer / shabeer v c

def shaf(n):
l=range(3,n+1,2)
mi=n
i=0
r=0
print l
while l[i]<n-1:

for j in range(2,l[i]):
if l[i]%j==0:
r=5
if r==0:
print l[i]


r=0
i=i+1


if __name__ == "__main__":
print "prime numbers from 2 to <101 "
shaf(100)

Answer / karthik

void main()
{
int i,j,m;
for(i=1;i<=100;i++
{
m=0
for(j=1;j<i;j++)
{
if(i%j==0)
m++;
}
if(m==0)
printf("%d",i);
getch();
}

Answer / sathya

#include<iostream.h>
void main()
{
int n,a;
cout<<"enter the limit";
cin>>n;
for(i=1;i<=n;i++}
{
if(i=1)
{
cout<<"1 is neither a prime nor a composite no";
}
else if(i%1==0|i%i==0)
{
cout<<i<<"is a prime number";
}
}
}

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