Answer / vignesh1988i

for a)
#include<stdio.h>
#include<conio.h>
void main()
{
int n;
printf("enter the number of terms :");
scanf("%d",&n);
for(int i=0;i<=n+i;i++)
{
for(int j=0;j<n-1 ;j++)
printf(" ");
for(j=0;j<=(2*i);j++)
printf("* ");
printf("\n");
n--;
}
getch();
}

for b):
#include<stdio.h>
#include<conio.h>
void main()
{
int n;
printf("enter the no. of terms :");
scanf("%d",&n);
for(int i=1;i<=5;i++)
{
printf("\n");
if(i==1 || i==n)
{
for(j=0;j<n;j++)
printf("* ");
}
else
{
printf("* ");
for(j=0;j<n-2;j++)
printf(" ");
printf("* ");
}
}
getch();
}

Answer / vutukuru

#include<stdio.h>
main()
{
int i,j,n=5;
clrscr();
for(i=0;i<n-4;i++)
{
printf("*");
}
printf("\n");
for(i=0;i<n-2;i++)
{
printf("*");
}
printf("\n");
for(i=0;i<n;i++)
{
printf("*");
}
getch();
}

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