how to find sum of digits in C?
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Answer / pooja
main()
{
int n,i,sum=0,r;
printf("enter the value");
scanf("%d",&n);
while(n!=0)
{
r=n%10;
n=n/10;
sum=sum+r;
}
printf("\nsum of digits is %d",sum);
}
| Is This Answer Correct ? | 57 Yes | 11 No |
Answer / bhagwat
main()
{
int n,i,sum=0,r;
printf("enter the value");
scanf("%d",&n);
while(n!=0)
{
r=n%10;
n=n/10;
sum=sum+r;
}
| Is This Answer Correct ? | 53 Yes | 19 No |
Answer / leninraj
main()
{
int n,i,sum=0,r;
printf("enter the value");
scanf("%d",&n);
for(i=0;i<=5;i++)
{
r=n%10;
n=n/10;
sum=sum+r;
}
| Is This Answer Correct ? | 57 Yes | 32 No |
Answer / pankaj khaitan
main()
{
int n,i,sum=0,r;
printf("enter the value");
scanf("%d",&n);
while(n)
{
rem=num%10;
sum=sum+rem;
num=num/10;
}
printf("sum = %d",sum);
}
| Is This Answer Correct ? | 40 Yes | 15 No |
Answer / keerthireddy
#include<stdio.h>
#include<conio.h>
main()
{
int n,i,sum=0,r;
printf("enter the value");
scanf("%d",&n);
while(n>0)
{
r=n%10;
sum=sum+r;
n=n/10;
}
printf("sum = %d",sum);
}
output:
3456
how it works as follows:
3456%10 means it gives reminder as 6
6 will be added to the sum
3456/10 means it gives quotient as 345
then again loop is executing until the n value is 0
finally the result as 6+5+4+3=18
| Is This Answer Correct ? | 9 Yes | 1 No |
Answer / d. prashant
#include<stdio.h>
#include<conio.h>
main()
{
int n,i,sum=0,r;
printf("enter the value");
scanf("%d",&n);
while(n)
{
rem=num%10;
sum=sum+rem;
num=num/10;
}
printf("sum = %d",sum);
}
| Is This Answer Correct ? | 7 Yes | 3 No |
Answer / anil kumar nahak
void main()
{
int n,i,sum=0,r;
printf("enter the value");
scanf("%d",&n);
while(n>0)
{
rem=num%10;
sum=sum+rem;
num=num/10;
}
printf("sum = %d",sum);
}
| Is This Answer Correct ? | 3 Yes | 3 No |
Answer / sarthak patwal
#include <stdio.h>
#include <conio.h>
void main()
{
clrscr();
int a,b,c,d;
printf ("Enter the number");
scanf ("%d",a);
b=a%10;
c=a/10;
d=b+c;
printf ("The sum of digits is %d",d);
getch();
}
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / nona
int n1, n2, sum;
Console.WriteLine("plz type the 1st number");
n1 = int .Parse (Console .ReadLine ());
Console.WriteLine("plz type the 2nd number");
n2 = int .Parse (Console .ReadLine ());
sum = n1 + n2;
| Is This Answer Correct ? | 0 Yes | 0 No |
Reverse the part of the number which is present from position i to j. Print the new number. eg: num=789876 i=2 j=5 778986
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