how to find number of columns in a table in sql server 2000
and 2005 also
Answers were Sorted based on User's Feedback
Answer / kumar.t
Select Count(Column_Name) As NoOfColumns From
Information_Schema.Columns Where table_Name='Company'
| Is This Answer Correct ? | 22 Yes | 2 No |
Answer / jerry joseph
SELECT count(*) NoOfColumns FROM SYSCOLUMNS
WHERE id= (Select id from SYSOBJECTS where name = 'TableName')
| Is This Answer Correct ? | 14 Yes | 6 No |
Answer / amit
SELECT count(*) NoOfColumns FROM SYSCOLUMNS
WHERE id= (Select id from SYSOBJECTS where name
= 'TableName')
| Is This Answer Correct ? | 6 Yes | 2 No |
Answer / naren
sp_help tablename
another command is
select name from syscolumns where id=object_id
('table_name')
| Is This Answer Correct ? | 6 Yes | 3 No |
Answer / sujitha
SELECT DISTINCT SYS.NAME,COUNT(*) FROM SYSOBJECTS SYS
INNER JOIN SYSCOLUMNS SYSCOL ON SYSCOL.ID=SYS.ID
WHERE SYS.XTYPE='U' GROUP BY SYS.NAME
| Is This Answer Correct ? | 3 Yes | 2 No |
Answer / anand k
--FOR Given Table Name.
SELECT COUNT(*) FROM SYS.COLUMNS
WHERE ID = OBJECT_ID('<TABLENAME>')
--For All UD Tables in the current DB
SELECT OBJ.NAME,COUNT(*)
FROM SYS.COLUMNS COL,SYS.OBJECTS OBJ
WHERE OBJ.OBJECT_iD = COL.OBJECT_ID
AND TYPE = 'U'
GROUP BY OBJ.NAME
| Is This Answer Correct ? | 4 Yes | 4 No |
Answer / anuruddha
SELECT
K_Table = FK.TABLE_NAME,
FK_Column = CU.COLUMN_NAME,
PK_Table = PK.TABLE_NAME,
PK_Column = PT.COLUMN_NAME,
Constraint_Name = C.CONSTRAINT_NAME
FROM INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS C
INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS FK ON
C.CONSTRAINT_NAME = FK.CONSTRAINT_NAME
INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS PK ON
C.UNIQUE_CONSTRAINT_NAME = PK.CONSTRAINT_NAME
INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE CU ON
C.CONSTRAINT_NAME = CU.CONSTRAINT_NAME
INNER JOIN (
SELECT i1.TABLE_NAME, i2.COLUMN_NAME
FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS i1
INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE i2 ON
i1.CONSTRAINT_NAME = i2.CONSTRAINT_NAME
WHERE i1.CONSTRAINT_TYPE = 'PRIMARY KEY'
) PT ON PT.TABLE_NAME = PK.TABLE_NAME
| Is This Answer Correct ? | 3 Yes | 3 No |
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