Answer / e v n raja

#include<stdio.h>
#include<conio.h>

void main()
{
int a[5],i,ele;


clrscr();

printf("enter the array elements
");

for (i=0; i<5; i++)
scanf("%d",&a[i]);

printf("Enter the element to be search
");
scanf("%d",&ele);

// searching for the element

for (i=0; i<5; i++)
{
if (a[i]==ele)
{
printf("Element found %d , position==%d",ele,i);
break;
}
}

} // end of main()

Answer / laxmi

#include<stdio.h>
#include<conio.h>
void main()
{
int a[5]={1,2,3,4,5};
int i;
clrscr();
printf("
enter the value");
scanf("%d",&i);
for(i=0;i<5;i++)
if(i<5)
{
printf("
the value is present=%d");
}
else
{
printf("
the value is absent=%d");
}
getch();
}

Answer / vs

#include<stdio.h>
#include<conio.h>
void main()
int a[5],i;
int e,t=0,p=0;
clrscr();
printf("enter the array of elements/n");
for(i=0;i<5;i++)
scanf("%d",&a[i]);
clrscr();
printf("enter the element to search/n");
scanf("%d",&e);
for(i=0;i<5;i++)
{
if(a[i]==e)
{
t=1;
p=i;
}
}
if(t==1)
printf("element found--%d/n position--%d",e,p);
else
printf("element not found/n");
getch();
}

Answer / satys

we can use any variable in the place of temp

Answer / aishwarya rajan

#include<iostream.h>
#include<conio.h>
void main()
{
int i,n,a[30];
char item;
cout<<"Enter the number of elements you would like to enter in the array: ";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"Enter the element"<<i+1<<" :";
cin>>a[i];
}
cout<<"Enter the element you are searching for in the array:";
cin>>item;
if(a[i]==item)
cout<<"The item does exist in the array!! it is the "<<i+1<<" element!!";
else
cout<<"The item is not found in the array!!";
getch();
}

Answer / priya chauhan

Find the presence of a given number in a set of numbers
using array. also find the position of the number.

Answer / jamshed

IF WE STORE ELEMENTS IN AN ARRAY :


import java.io.*;
class Search
{
public static void main()throws IOException
{
InputStreamReader isr=new
InputStreamReader(System.in);
BufferedReader br=new BufferedReader(isr);
int a[]={5,7,9,11,15,20,30,45,89,97};
int i,n,c=0;
System.out.println("Enter a Number to Search");
n=Integer.parseInt(br.readLine());

for(i=0;i<a.length;i++)
{
if(a[i]==n)
{
c++;
System.out.println("\nThe Number "+n+"
Does Exist");
System.out.println("The Position is
"+(i+1));
}
}
if(c==0)
System.out.println("Search Element Not Found");
}
}

Answer / all

#include<stdio.h>

Badboy is defined who has ALL the following properties: Does not have a girlfriend and is not married. He is not more than 23 years old. The middle name should be "Singh" The last name should have more than 4 characters. The character 'a' should appear in the last name at least two times. The name of one of his brothers should be "Ram" Write a method: boolean isBadBoy(boolean hasGirlFriend , boolean isMarried, int age , String middleName , String lastName , String[] brotherName); isHaveGirlFriend is true if the person has a girlfriend isMarried is true if the person is married age is the age of the person middleName is the middle name of the person lastName is the last name of the person brotherName is the array of the names of his brothers

0 Answers  

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