Answer / abhishek jaiswal

select salary from employees a where &nth_highest_salary =(select count(distinct salary)
from employees b where a.salary<=b.salary)
/

Answer / mohammed irfan

SELECT sal1 "salary"
FROM (SELECT ROWNUM rownum1 ,sal1
FROM (SELECT sal sal1
FROM emp
ORDER BY sal DESC
)
)
WHERE rownum1=:p_highest;

Note:- 'p_highest' here we can give the number as we want
to display the highest salary.

Answer / ruma

select *from emp order by sal desc limit 1,1

Answer / hitesh pundir

select max(salary)from m1 where salary <>(select max(salary)
from m1)

Answer / vinay

It works gr8...

select max(salary) from <table_name> where salary<(select
max(salary)from <table_name>)

Answer / mallika

SELECT salary FROM employee a
WHERE &n IN (SELECT COUNT(*) FROM employee b
WHERE a.salary <= b.salary)

Answer / neeraj

SELECT DISTINCT(SAL) FROM EMP
WHERE SAL=(SELECT MIN(SAL) FROM (SELECT SAL FROM EMP ORDER
BY SAL DESC)
WHERE ROWNUM<=2);

Answer / sathiavathi

select max(salary) from employee where salary!=(select max
(salary) from employee);

Answer / sarojkant

select max(salary ) from emp table where sal<(select max
(salary)from emp table)

Answer / sarojkant

select sal from emp
where rownum=2
order by sal desc

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