Answer / navs

if we take the array as
arr[]={1,4,7,2,10,0,6}

get the count

int count =6;
int max =arr[0];
int smax;

for (i=0;i<=count;i++)
{
if(max<arr[i])
{
smax=max;
max=max[i];
}
}

smax would give the second largest number

Answer / vili

// this deals with negative numbers as well
int getSecondMax( int* pArray, int nSize )
{
int nMax = pArray[0];
int n2ndMax = pArray[0];
for ( int i = 1; i < nSize; i++ )
{
if ( nMax < pArray[i] )
{
n2ndMax = nMax;
n2ndMax = pArray[i];
}
}
return n2ndMax;
}

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