Answer / cvs

class testing{
public testing(){
System.out.println("Hello ");
}
}
public class TestClass{
static testing t = new testing();
public TestClass(){
}
}

Answer / s.j

in c language
#define main begin
void begin()
{
printf("HELLO");
}

Answer / shanu zabeen

class testing
{
public testing()
{
System.out.println("world");
}
}

public class Demo
{
static testing t = new testing();
public Demo()
{
}
}

Answer / harsha

#include<stdio.h>
#define func main
int func()
{
printf("Virat
");
}

Answer / unknown

You can use Macros to do this job if the goal is not to use the name "main" in the function.
Example 1:
#define func main
void func()
{
printf("hello");
}

Example 2:
If the word main should not be displayed then,

#define func m##a##i##n
void func(){
printf("hello");
}


If you really want not to use main function at all, then you have to override the main function call manually. The call to the main function is made by another function called "_start()". The function is called by the compiler and then the main function is called by that.
#include<stdio.h>
#include<stdlib.h>
void _start(){
puts("Hello World
");
exit(0);
}

Here, you have to compile the program with gcc -nostartfiles, so that the startfile(ie main) is being overridden with your code.

Answer / prakash

#define begin main
void begin()
{
pf("hi");
getch();
}

Answer / s.j

in c language
#define begin main();
void begin
{
printf("HELLO");
}

Answer / vijay nag

use a constructor and declare a global object.

class message
{

public:
message("Hello world\n");
}a;
void main(){}

Answer / amit dubey

class testprint
{
static String print=testprint.toString("test");
public static String toString(String s)
{
System.out.println("I am Here");
return s;
}
}

Answer / jaya

Sorry. Missing return statement in the former post

public class classWithoutMain {
private static int x = load();
private static int load() {
System.err.println("This message will be printed");
System.exit(0);
return 0;
}
}

Write a program to convert a decimal number to binary form?

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Financial: credit card number validation) Credit card numbers follow certain patterns. A credit card number must have between 13 and 16 digits. It must start with: &#9632; 4 for Visa cards &#9632; 5 for Master cards &#9632; 37 for American Express cards &#9632; 6 for Discover cards In 1954, Hans Luhn of IBM proposed an algorithm for validating credit card numbers. The algorithm is useful to determine whether a card number is entered correctly or whether a credit card is scanned correctly by a scanner. All credit card numbers are generated following this validity check, commonly known as the Luhn check or the Mod 10 check, which can be described as follows (for illustration, consider the card number 4388576018402626): 1. Double every second digit from right to left. If doubling of a digit results in a two-digit number, add up the two digits to get a single-digit number. 2 * 2 = 4 2 * 2 = 4 4 * 2 = 8 1 * 2 = 2 6 * 2 = 12 (1 + 2 = 3) 5 * 2 = 10 (1 + 0 = 1) 8 * 2 = 16 (1 + 6 = 7) 4 * 2 = 8 2. Now add all single-digit numbers from Step 1. 4 + 4 + 8 + 2 + 3 + 1 + 7 + 8 = 37 3. Add all digits in the odd places from right to left in the card number. 6 + 6 + 0 + 8 + 0 + 7 + 8 + 3 = 38 4. Sum the results from Step 2 and Step 3. 37 + 38 = 75 5. If the result from Step 4 is divisible by 10, the card number is valid; otherwise, it is invalid. For example, the number 4388576018402626 is invalid, but the number 4388576018410707 is valid. Write a program that prompts the user to enter a credit card number as a long integer. Display whether the number is valid or invalid. Design your program to use the following methods: /** Return true if the card number is valid */ public static boolean isValid(long number) /** Get the result from Step 2 */ public static int sumOfDoubleEvenPlace(long number) /** Return this number if it is a single digit, otherwise, return * the sum of the two digits */ public static int getDigit(int number) /** Return sum of odd place digits in number */ public static int sumOfOddPlace(long number) /** Return true if the digit d is a prefix for number */ public static boolean prefixMatched(long number, int d) /** Return the number of digits in d */ public static int getSize(long d) /** Return the first k number of digits from number. If the * number of digits in number is less than k, return

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