Answer / shiva

I think U need this .......

/*****************************************************/
import java.util.*;

class TreeSetDemo {
public static void main(String args[]) {
// Create a tree set.
TreeSet<String> ts = new TreeSet<String>();

// Add elements to the tree set.
ts.add("C");
ts.add("A");
ts.add("B");
ts.add("E");
ts.add("F");
ts.add("D");

System.out.println(ts);
}
}

/******************************************************/
The output from this program is shown here:
[A, B, C, D, E, F]
/*******************************************************/

/********************************
************ AND ************
**********************************/



import java.util.*;

class HashSetDemo {
public static void main(String args[]) {
// Create a hash set.
HashSet<String> hs = new HashSet<String>();

// Add elements to the hash set.
hs.add("B");
hs.add("A");
hs.add("D");
hs.add("E");
hs.add("C");
hs.add("F");

System.out.println(hs);
}
}

/**************************************/
The following is the output from this program:
[D, A, F, C, B, E]
/****************************************/

Answer / r.jude silvester

You can use any of Collections like Vector,ArrayList or HashSet etc.

Answer / madhura

impotr java.util.*;
class store
{
public static void main(String args[])
{
Vector v=new Vector();
for(int i=0;i<10;i++)
{
v.addElement(i);
}
System.out.println("the elements in vector are"+v);
}}

Answer / r.jude silvester

You can use any of the Collections for eg.ArrayList

Answer / shanu zabeen

import java.util.*;
import java.io.*;
public class Store
{
public static void main(String args[])
{
System.out.println
("enter number of elements to be stored");
Scanner cin=new Scanner(System.in);
int n=cin.nextInt();
Vector v=new Vector();
for(int i=0;i<n;i++)
{
v.addElement(i);
}
System.out.println("the elements in vector are"+v);
}}

Answer / karthik

link list i think..

Answer / kiran

please post the answer...



thanks and regards
kiran.y

Answer / ashok kumar

using
BufferedReadered br=new BufferedReader(new InputStreamReader
(System.in));
while (br.readline)
System.out.println(br);



















B

Financial: credit card number validation) Credit card numbers follow certain patterns. A credit card number must have between 13 and 16 digits. It must start with: &#9632; 4 for Visa cards &#9632; 5 for Master cards &#9632; 37 for American Express cards &#9632; 6 for Discover cards In 1954, Hans Luhn of IBM proposed an algorithm for validating credit card numbers. The algorithm is useful to determine whether a card number is entered correctly or whether a credit card is scanned correctly by a scanner. All credit card numbers are generated following this validity check, commonly known as the Luhn check or the Mod 10 check, which can be described as follows (for illustration, consider the card number 4388576018402626): 1. Double every second digit from right to left. If doubling of a digit results in a two-digit number, add up the two digits to get a single-digit number. 2 * 2 = 4 2 * 2 = 4 4 * 2 = 8 1 * 2 = 2 6 * 2 = 12 (1 + 2 = 3) 5 * 2 = 10 (1 + 0 = 1) 8 * 2 = 16 (1 + 6 = 7) 4 * 2 = 8 2. Now add all single-digit numbers from Step 1. 4 + 4 + 8 + 2 + 3 + 1 + 7 + 8 = 37 3. Add all digits in the odd places from right to left in the card number. 6 + 6 + 0 + 8 + 0 + 7 + 8 + 3 = 38 4. Sum the results from Step 2 and Step 3. 37 + 38 = 75 5. If the result from Step 4 is divisible by 10, the card number is valid; otherwise, it is invalid. For example, the number 4388576018402626 is invalid, but the number 4388576018410707 is valid. Write a program that prompts the user to enter a credit card number as a long integer. Display whether the number is valid or invalid. Design your program to use the following methods: /** Return true if the card number is valid */ public static boolean isValid(long number) /** Get the result from Step 2 */ public static int sumOfDoubleEvenPlace(long number) /** Return this number if it is a single digit, otherwise, return * the sum of the two digits */ public static int getDigit(int number) /** Return sum of odd place digits in number */ public static int sumOfOddPlace(long number) /** Return true if the digit d is a prefix for number */ public static boolean prefixMatched(long number, int d) /** Return the number of digits in d */ public static int getSize(long d) /** Return the first k number of digits from number. If the * number of digits in number is less than k, return

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