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What will happen when the following code is run:
int x;
while(x<100)
{
cout<<x;
x++;
}
1) The computer will output "0123...99"
2) The computer will output "0123...100"
3) The output is undefined
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Answer / nk
Output is undefined because initially variable 'x' is not
initialized and may contain some garbage value.
However if we initialize 'x' to 0 then choice#1 is correct.
| Is This Answer Correct ? | 13 Yes | 0 No |
Answer / d n gavade
The Answer is 3)The Output is undefined because x is not
initialised and its datatype is auto int so that its inital
value will be garbage.
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / deepanker aggarwal
the answer is 3 because x is not initialised and it may
contain any garbage value
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / rakesh
the output is undefined
because c++ do not implicitly initialised the varible. it
gives garbage value for uninitialized variables
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / ibrazileasum
The initial value of x is not defined to '0' hence the complier will not start from 0 as initial value. This is a garbage error to the compiler
| Is This Answer Correct ? | 0 Yes | 0 No |
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