COMP-3 field occupy ?
Answers were Sorted based on User's Feedback
Answer / phani
if n is even, then n/2 + 1 bytes
if n is odd, then int(n+1/2) bytes
every time rightmost 1/2 byte is used to store sign value.
Is This Answer Correct ? | 5 Yes | 3 No |
Answer / sp
Its not even and odd. Its jst (n+1)/2. If aftre calculation
we are getting decimal value then it will roundeed to next
value.
Is This Answer Correct ? | 4 Yes | 2 No |
Answer / vasanth
No it should be M+N/2 for bytes allocation in case of
variable var1 pic 9(6)v99 comp-3
where M=6 and N=2
The limit of comp-3 variable declartion is EX: var1 s9(18)
comp-3
Is This Answer Correct ? | 9 Yes | 9 No |
Answer / vasanth
I guess there is no Odd and Even theory in case of COMP-3
variable memory allocation calculation.
If there is an fractional output of M+N/2+1
Then the value is rounded off to its next value accordingly.
Is This Answer Correct ? | 2 Yes | 2 No |
Answer / sid
Hi Friends;
Here I want to contribute a few lines in this discussion,
those might helpful to understand it very clearly.
BINARY
Specified for binary data items. Such items have a decimal
equivalent
consisting of the decimal digits 0 through 9, plus a sign.
Negative numbers
are represented as the two's complement of the positive
number with the same absolute value. The amount of storage
occupied by a binary item depends on the number of decimal
digits defined in its PICTURE clause:
1 through 4 2 bytes (halfword)
5 through 9 4 bytes (fullword)
10 through 18 8 bytes (doubleword)
The operational sign for ?big-endian? binary data (such as
OS/390 and VM) is contained in the left most bit of the
binary data. The operational sign for ?little-endian? binary
data is contained in the left most bit of the right most
byte of the binary data.
PACKED-DECIMAL
Specified for internal decimal items. Such an item appears
in storage in
packed decimal format. There are 2 digits for each character
position, except for the trailing character position, which
is occupied by the low-order digit and the sign. Such an
item can contain any of the digits 0 through 9, plus a sign,
representing a value not exceeding 18 decimal digits.
The sign representation uses the same bit configuration as
the 4-bit sign
representation in zoned decimal fields.
Following is the range I found in a IBM COBOL Programming manual
Picture Storage representation Numeric values
S9(1) through S9(4) Binary half-word (2 bytes) -32768
through +32767
S9(5) through S9(9) Binary full-word (4 bytes)
-2,147,483,648 through
+2,147,483,647
S9(10) through S9(18) Binary double-word (8bytes)
-9,223,372,036,854,775,808 through +9.223,372,036,854,775,807
9(1) through 9(4) Binary half-word (2 bytes) 0 through 65535
9(5) through 9(9) Binary full-word (4 bytes) 0 through
4,294,967,295
9(10) through 9(18) Binary double-word (8bytes) 0 through
18,446,744,073,709,551,615
Is This Answer Correct ? | 1 Yes | 2 No |
Comp3 will occupy from s9(1) to s9(18) . it wont exceed more
than it . So max value of comp3 is 10 bytes
i.e, 18/2 +1 = 9 + 1 = 10 bytes .
I thk i am correct .
Is This Answer Correct ? | 1 Yes | 2 No |
Answer / mf buzz
Hi,
for pic 9(n) comp-3.
if n is even, then n/2 + 1 bytes
if n is odd, then int(n/2) bytes.
Is This Answer Correct ? | 5 Yes | 9 No |
What are declaratives and what are their uses in cobol?
What is rmode(24)
If we put three reads in COBOL in the same para one after the other, to read a PS file,will it read the same record thrice or it will read three records sequentially? For example : Input File 01 02 03 Para 900 Read infile Display Infile rec Read infile Display infile rec Read infile Display infile rec. What will be the output?
What is different between variable length and fixed length?
what is the use of filler in cobol programing?
01 a pic 9(6) value is 123456 01 b pic 9(3) move a to b wht will be the value ?
what is a zoned decimal data type and how it will be stored?
88 level entry is used for (a) data items in WORKING-STORAGE SECTION (b) items with RENAMES clause (c) condition-names (d) None of the above
We have 3 programms A,B,C.In the middle of the program A the controls goes to program B and in the middle of the program B control wants to go program C,after completion of program C again control comes to program B and again after completion of program B control comes to program A.How the process will takes and what are the controls we use for that process.If it is possible anybody of you explain with example?
What is XDC ?
what is SYNCHRONIZATION?
What is the difference between copy and include in cobol?