A 12 address lines maps to the memory of
[a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none
Answers were Sorted based on User's Feedback
Answer / prasanna hugar
1) 12 address is ma12 address is mapped to 2^12 = 4096 bits
2) 4096/8 = 512bytes( dividing by 8 because converting bits
to bytes 8 bits = 1 bytes)
3) 512/1024 = 0.5 K bytes
I think my answer is cleared your problem
| Is This Answer Correct ? | 31 Yes | 1 No |
Answer / indermohan singh
b. Because 2^12= 4Kbits=4/8Kbytes=0.5 Kbytes
| Is This Answer Correct ? | 21 Yes | 5 No |
Answer / eumine
Sorry i mistakenly wrote the answer [b] it is [d].
| Is This Answer Correct ? | 23 Yes | 10 No |
Answer / ahmed eldesokey
12 address is mapped to 2^12 = 4096 byte
so
4096 byte / 1024 = 4 Kbyte
then the answer is [ d ] none it is mapped on 4 KB
| Is This Answer Correct ? | 18 Yes | 10 No |
Answer / eumine
12 address lines can map to 4096 bytes of memory.
So Answer is [b].
| Is This Answer Correct ? | 23 Yes | 16 No |
Answer / saki
2^n bits n is no of address lines so 2^12=4096 bits
4096/8= 512 bits which is 0.5 k byte
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / divya
Here 2^12=4096 but it is in bit so need to convert it into byte so we do 4096/8=512=0.5k byte. so the answer is b)
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / singh
Since word size not given so assuming that at each location 1 bit lies... We get 12 address lines to map 4096 bits..i.e .5 Kbytes... !!
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / sravz
here why 4bytes is divided by 8bytes ? can you explain me clearly
| Is This Answer Correct ? | 1 Yes | 4 No |
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