2^n bits n is no of address lines so 2^12=4096 bits 4096/8= 512 bits which

A 12 address lines maps to the memory of

[a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none

Question Posted / saki

Answer Posted / saki

2^n bits n is no of address lines so 2^12=4096 bits
4096/8= 512 bits which is 0.5 k byte

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