int i =10
main()
{
int i =20,n;
for(n=0;n<=i;)
{
int i=10
i++;
}
printf("%d", i);
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Answer / jai
printf() will never be executed since for() is an infinite
loop.
| Is This Answer Correct ? | 30 Yes | 2 No |
Answer / vignesh1988i
it will not print i value at all , since the loop is always
true for all cases. since the termination condition is
depending upon n&i,always n<=i, what ever possibe positive
value greater than zero ,it may be.
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / dips
it doesnt have any terminating condition so it will be
infinite loop ,no output
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / guest
the print would be 20.
the problem is about scope. the first i=10 is global scope.
But inside main() comes function scope. So i=20. The i
inside the for loop is of block scope and does not affect
the i outside it.
| Is This Answer Correct ? | 5 Yes | 9 No |
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