Answer / rajesh kumar s

int main()
{
int n,num,i;
printf("enter the num");
scanf("%d",&num);
n=num;
printf("\n");
for(i=2;i<=n/2;i++)
{
if(n%i==0)
{
prime(i);
}
}
}

void prime(int x)
{
int i,f=0;
for(i=2;i<=x/2;i++)
{
if(x%i==0)
{
f=1;
break;
}
}
if(f==0)
printf(" %d",x);

}

Answer / priyanka chauhan

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,n;
clrscr();
printf("Enter the no: ");
scanf("%d",&n);
for(j=2;j<=n;j++)
{
if(n%j==0)
{
for(i=2;i<=j-1;i++)
{
if(j%i==0)
break;
}
if(i==j)
printf("%d ",j);
}
}
getch();
}

Answer / sourav das

#include<stdio.h>
#include<conio.h>

void main()
{
int i,j,k,l,n;
clrscr();
printf("Enter The Number:");
scanf("%d",&n);
i=1;
while(i<=n)
{
if(n%i==0)
{
j=1;
k=0;
l=1;
while(l<=j)
{
if(j%l==0)
k++;
l++;
}
if(k==2)
{
printf("\n%d is the prime factor of %d",l-1,n);
}
}
i++;
}
getch();
}

Answer / shruthi chandran

voiid primeFactors(int n)
{
while (n%2 == 0)
{
printf("%d ", 2);
n = n/2;
}
for (int i = 3; i <= sqrt(n); i = i+2)
{

while (n%i == 0)
{
printf("%d ", i);
n = n/i;
}
}

if (n > 2)
printf ("%d ", n);
}

Answer / kalee

Pseudo code: Algorithm ....

If N is the integer, then, any number greater than sqrt(N) will not be a factor of that integer...

so it is enough to check till sqrt(N) integers, that is it is divisible or not... further, if N is odd... forget all the even integers, as they cannot be a part of factors.. :)

Happy coding...

Answer / varshil shah

#include<stdio.h>
#include<conio.h>
void factors(int);
void main()
{
int num,fact,i;
clrscr();
printf("\n Enter a number :::");
scanf("%d",&num);
if(num==2)
{
factors(num);
}
else
{
for(i=2;i<=num;i++)
{
if(num%i==0)
{
factors(i);
}
}
}
getch();
}
void factors(int n)
{
int i,notprime=0;
if(n==2)
{
printf("\n Prime factor is 2");
}
else
{
for(i=2;i<n;i++)
{
if(n%i==0)
{
notprime++;
}
}
if(notprime==0)
{
printf("\n Prime factor is %d",i);
}
}
}

Answer / bibek

/*Program To Generate The Prime Factors Of An Entered
Numbers*/

/*Header Files*/
#include<stdio.h>


/*Function Prototypes*/
void factorcheck(long unsigned int prime,long unsigned int
num );
void primefind(long unsigned int num, long unsigned int
startnum);

void main()
{

long unsigned int num;

printf("\n Enter A Positive Number:");
scanf("%d", &num);
printf("\n ");

/*Call To the primefind() function*/
primefind(num,
1); /*Find
a prime less than the given number*/

if (num==0)
{
printf(" 0 \n \n");
}
else if (num==1)
{
printf(" 1 \n \n");
}
else
{
printf("\b \n
\n "); /*Delete the
extra 'x' left in the end*/
}

}

void primefind(long unsigned int num, long unsigned int
startnum)
{

long unsigned int counter1, counter2, primecheck;
char primestat;

for(counter1 = startnum; counter1<=num; counter1++)
{

for (counter2 = 2; counter2< counter1; counter2++)
{


primecheck = counter1 %
counter2; /* Check If The Chosen Number
(counter1) is divisible

by numbers less than it excluding 1*/
if (primecheck != 0 )
primestat
= 't'; /*The Number Is
Prime*/

else /*(So
Far)*/
{
primestat
= 'f'; /*The Number Is
Not Prime*/
break;
}

}

if (primestat =='t' || counter1 ==2)
{
factorcheck
(counter1,num); /*This Calls
The Function factorcheck()*/

break;
/* which checks if the prime number */
}
/*generated is a factor of the given
number*/


}

}

void factorcheck(long unsigned int prime, long unsigned int
num)
{
long unsigned int remainder;

remainder = num%prime;

if (remainder ==
0) /*since the remainder is 0,
the prime number is a factor*/
{
printf("%dx", prime);
primefind((num/prime), 1); /*Find
Another prime number*/
return;
}
else
primefind(num, prime+1); /*Since
The Generated Prime is not a factor,*/
/*the function
checks for the next prime number available*/
}

Answer / mohammad nasim

include<stdio.h>
main()
{
int n;
printf("Enter a positive integer: ");
scanf("%d",&n);
printf("\nThe prime factors are:\n");
while((n/2)!= 0 || (n/3)!=0)
{
if(n%2==0)
{
printf("\t2");
n=n/2;
}
else
{
if(n%3==0)
{
printf("\t3");
n = n/3;
}
else
{
printf("\t%d",n);
break;
}

}
}

}

Answer / courage

#include<stdio.h>

int main()

{

int num=0;

printf("Enter number\n");

scanf("%d",&num);

int i,count=0,j;

for (i=1;i<=num;i++)

{

if (num%i==0)

{

for (j=1;j<=i;j++)

{

if(i%j==0)

{

count=count+1;

}

}

if (count==2)

{

printf("%d",i);

}

count=0;




}

}

}

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