Answer / devi

#include<stdio.h>
#include<conio.h>
void main()
{
int a[200],i,n;
float sum=0,avg;
clrscr();
printf("Enter the n values");
scanf("%d",&n);
for(i=0;i<n;i++)
{
sum=sum+a[i];
}
avg=sum/n;
printf("Sum of %d array values is:%f",n,avg);
getch();
}

Answer / pradeepnair

#include<stdio.h>
#include<conio.h>

void main()
{
int val1;
int val2;
int size=0;
int a,b[100];
int i,n,j,k=1;
int sum=0;
int sum1=0;
printf("enter the no of values to be added");
scanf("%d",&val1);
for(i=0;i<val1;i++)
{
scanf("%d",&a);
sum=sum+a;
}
System.out.println("the sum is"+sum);
while(sum>0)
{
val2 = sum%10;
sum=sum/10;
b[k]=val2;
size=size+1;
k--;
}
printf("the values in array are");
for(i=0;i<size;i++)
{
printf("/n",b[i]);

}

for(j=0;j<size;j++)
{
sum1=sum1+b[j];
}
printf("the sum of values an array is $d",sum1)

getch();
}

int a[3][5]={ {1,2,3,4,5],{2,3,4,5,6},{10,11,12,13,14}}; int *p=&a; printf(“%d”,*(*(x+1)+3));

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