How long does this loop run:
for(int x=0; x=3; x++)
a) Never
b) Three times
c) Forever
- 17 Answers
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Answer / pracheer gupta
what r u saying guys..
the loop will run c) forever
this is bcoz in the termination part it is actually x=3 and
not x==3.
x=3 will always evaluate to true and hence the loop is
executed infinite times.
| Is This Answer Correct ? | 91 Yes | 11 No |
Answer / manju
The correct and verified answer is the loop runs forever
the answer is c. it is so becoz in condition part we are
giving i=3 and not i==3.
so it executes infinite times.
| Is This Answer Correct ? | 32 Yes | 3 No |
Answer / eric
The loop will run forever.
K.premalatha is the foolest lady I have ever met.
| Is This Answer Correct ? | 17 Yes | 3 No |
Answer / john
the loop runs forever guys....
have you tried this? without trying u r giving the random answers?
Sentrix, Eric, Manju,Pracheer Gupta are right...
other guys please try it....
| Is This Answer Correct ? | 17 Yes | 4 No |
Answer /
#include<stdio.h>
main()
{
for(int x=0; x=3; x++)
printf("Forever.....");
}
| Is This Answer Correct ? | 13 Yes | 2 No |
Answer / divya
hai john I tried this in online compiler but it shows some errors....didnt give exact ans...Is there any other ways to conform this answer.
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / awaneesh dubey
Never . It will show compile time error . boolean required
at the terminationa condition not int . i.e. it should be
for(int x=0; x==3; x++) not for(int x=0; x=3; x++) .
x=3 will cause compilation error. So answer is never .
| Is This Answer Correct ? | 1 Yes | 1 No |
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