Answer / v.karthikeyan

#include <stdio.h>
main()
{
int num;

printf("Enter a number to know the entered number is odd or
even \n");
scanf("%d",&num);

if (num%2==0)
{
printf(" The number is Even");
else
printf(" The number is Odd")
}
getch();
}

Answer / dwarika

#include<stdio.h>
#include<conio.h>
int main()
{
clrscr();
int a;
printf("enter the no");
scanf("%d",&a);
if(a%2==0)
{
printf("no is even");
}
else
{
printf("odd no");
}
getch();
return 0;
}

Answer / shruti

to print numbers which are even from 0 to 100

main()
{
int i;

puts("THE EVEN NUMBERS ARE:");

for(i = 0 ; i <= 100 ; i++)
{
if(i%2 == 0)
printf("%d", i);
}

}

Answer / sameer.chaudhari

main()
{
int num;

printf("Plz enter the number :=> ");
scanf("%d",&num);

if (!(num & 1))
printf("Even");

getch();
}

Answer / shahbaz

void main()
{
int a,b;
cout<<"Enter number to check is it Even or Odd";
cin>>a;
if(a>=0)
{
if(a%2==0)
{
cout<<"The number is Even ";
}
else
{
cout<<"Number is Odd ";
}
}
else
{
Cout<<"Number is Lesser than Zero 0";;
}
getch();
}

Answer / nirdesh pal

#include<stdio.h>
#include<conio.h>
void main()
{
int i;
printf("enter the number");
scanf("%d",&i);
if(i%2==0)
{
printf("number is even");
else
printf("number is odd");
}
getch();
}

Answer / k.naveen kumar

#include<stdio.h>
#include<conio.h>
main()
{
int a;

printf("Please enter the number :=> ");
scanf("%d",&a);

if (a%2==0)
printf("Even");
else
printf("odd");
getch();
}

Answer / mehak saini

include<stdio.h>
include<conio.h>
void main()
{
inti,num;
printf("enter the number")
scanf(%d",&num);
for(i=1;i=<num;i+1)
{
if(i%2==0)
{
printf("%d",i);
}
}
getch();
}

Answer / joe

#include<stdio.h>
//#include<conio.h>

int main()
{
//clrscr();
int *a;
printf("\nenter the no\n");
scanf("%d",&a);
if(*a <0)
{
printf("\nEnter correct number :\n");
}
else if(*a%2==0)
{
printf("no is even");
}
else
{
printf("odd no");
}
getch();
main();
}

Answer / kannan

what function will do


if (!(num & 1))

How would you use the functions fseek(), freed(), fwrite() and ftell()?

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