How to get Links count in an web application,without
descriptive programming?

Answers were Sorted based on User's Feedback



How to get Links count in an web application,without descriptive programming?..

Answer / saidev

You can just palce page check point on that page,it will
give you the details like number of images ,number of links
etc in the page.

Is This Answer Correct ?    4 Yes 0 No

How to get Links count in an web application,without descriptive programming?..

Answer / chaitu

This Script is Helpfull to count the No.of links in a web
page

Step1: Set Objects = Browser("BrowserName").Page
("PageName").ChildObjects

Step2: Objectcount = Objects.count
Linkcount = 0
Step3: For i = 1 to Objectcount-1

Link = Objects(i).GetROProperty("micclass")
If Link = "Link" Then
Linkcount = Linkcount+1
msgbox Linkcount
End If
Next
msgbox Linkcount ' It show total number links

Is This Answer Correct ?    7 Yes 5 No

How to get Links count in an web application,without descriptive programming?..

Answer / raghava

Hi guys
Here we have to use the description object.Its working with
me.Just try it out.



Set oDesc = Description.Create()
oDesc("micclass").Value = "Link"
Set Lists = Browser("Google").Page("Google").ChildObjects
(oDesc)
NumberOfLists = Lists.Count()
linkcnt = 0
For i = 0 To NumberOfLists - 1
linkcnt = linkcnt+1

Next
msgbox linkcnt

Regards
raghava

Is This Answer Correct ?    2 Yes 0 No

How to get Links count in an web application,without descriptive programming?..

Answer / priya

here is an example to get the link count in google page
Just try out this

SystemUtil.Run ("www.google.com")
Set Links = Browser("title:=.*").Page("title:=.*").Object.Links
Msgbox "Total links: " & Links.Length

Is This Answer Correct ?    1 Yes 0 No

How to get Links count in an web application,without descriptive programming?..

Answer / a

POSTED BY -CHAITU
This Script is Helpfull to count the No.of links in a web
page

Step1: Set Objects = Browser("BrowserName").Page
("PageName").ChildObjects

Step2: Objectcount = Objects.count
Linkcount = 0
Step3: For i = 1 to Objectcount-1

Link = Objects(i).GetROProperty("micclass")
If Link = "Link" Then
Linkcount = Linkcount+1
msgbox Linkcount
End If
Next
msgbox Linkcount ' It show total number links
--------------
This code is not working.

Check it out.
Link = Objec(i).GetROProperty("micclass")
Error is here.

Is This Answer Correct ?    1 Yes 1 No

How to get Links count in an web application,without descriptive programming?..

Answer / kalyan

'Hi, we can use "innertext" as a unique property of link.
'Name may be changes in the runtime. And we can use the
index number to identify the link in the execution.
(NOTE:-We dont use index to retrive the child objects.why
because each child object have different index number.)

TRY THIS CODE:--------THIS WIL WORK FINE.

set olink=description.create()
oDesc("micclass").Value = "Link"
set chobj=browser().page().childobjects(olink)
n=chobj.count

msgbox n

for i=0 to n-1
val1=chobj(i).getroproperty("innertext")
msgbox val1
Next


Any doubts----mail to------ mskalyan.smile@gmail.com

Is This Answer Correct ?    1 Yes 1 No

How to get Links count in an web application,without descriptive programming?..

Answer / venkatesh.m

Hi friends,

set odesc=description.create()
set odesce("htmltag").value="a"
set lists=browser("b.name").page("p.name").childobjects
(odesc)
set counter=lists.count
msgbox "total no.of links"& counter
for i=0 to counter-1 step 1
set link=lists(i).getroproperty("name")
msgbox link,0,"curren link is"
Next


The above script works correctly.

Is This Answer Correct ?    0 Yes 2 No

How to get Links count in an web application,without descriptive programming?..

Answer / sudhir

Hi Friends ,
Above Ans #5 gives syntax mismatch error.
Find below correct code.

set odesc=description.create()
oDesc("micclass").Value = "Link"
set lists=browser("Welcome: Mercury Tours").page("Find a
Flight: Mercury").childobjects(odesc)
counter=lists.count
msgbox counter
for i=0 to counter-1 step 1
name=lists(i).getroproperty("name")
msgbox name,0,"curren link is"
Next

Is This Answer Correct ?    0 Yes 2 No

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