Answer / ajeesh

80

Answer / lime

40
40

30
60

- 10 cows
+ 20 days

if 40 cows can eat for forty days
then 20 cows can eat for 80 days

Answer / subash

All, the choice given are wrong ...

Let 'x' be the amount of grazed by a cow per day,

Let 'y' be the growth rate of grass per day,

Let 'z' be the amount of grass present initially,

So, 40 cows can graze (40*x) amount of grass per day and
(40*x*40) amount of grass for 40 days.

For 40 days, the growth of grass is (40*y)

So, (40*x*40) = (z + 40*y)

For 30 cows it takes 60 days, so,

(30*x*60) = (z + 60*y)

so, 1600x - 40y - z = 0 ----- 1

1800x - 60y - z = 0 ----- 2

Subtracting we get, 10x = y , Sub. 10x=y in 1 or 2, we get z
= 120y or z = 1200x

For, 20 cows,

20*x*N = z + N*y

Sub, 10x=y and (z=120y or 1200x), we get N = 120

Therefore, for 20 cows it takes 120 days to graze.

Answer / arun

80

Answer / ayyangar

options are suspectable...
isn't it?
answer is 120
For 25 cows the days required are 80..
observe the equations
(40*x-g)*40=(30*x-g)*60=(20*x-g)*n.
where x is grass units per a cow,
g grass units incresed.
n is number of days reqired...

Answer / meenu sharma

80

Answer / sujatha

b)80

Answer / -

b) 80

Answer / b.saravanan

answer is b)80 because the number of cows (20) which is
less than 30cows so obviously it will eat for more than 60
days

Answer / hariprasad

Answe is option B (i.e 80)

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