In a grass field, If there are 40 cows, they could eat for
40 days. If there are 30 cows, they could eat for 60 days.
Than if 20 cows, How much day they could eat?
a) 60 b) 80 c)55 d)50
Answers were Sorted based on User's Feedback
Answer / lime
40
40
30
60
- 10 cows
+ 20 days
if 40 cows can eat for forty days
then 20 cows can eat for 80 days
| Is This Answer Correct ? | 14 Yes | 2 No |
Answer / subash
All, the choice given are wrong ...
Let 'x' be the amount of grazed by a cow per day,
Let 'y' be the growth rate of grass per day,
Let 'z' be the amount of grass present initially,
So, 40 cows can graze (40*x) amount of grass per day and
(40*x*40) amount of grass for 40 days.
For 40 days, the growth of grass is (40*y)
So, (40*x*40) = (z + 40*y)
For 30 cows it takes 60 days, so,
(30*x*60) = (z + 60*y)
so, 1600x - 40y - z = 0 ----- 1
1800x - 60y - z = 0 ----- 2
Subtracting we get, 10x = y , Sub. 10x=y in 1 or 2, we get z
= 120y or z = 1200x
For, 20 cows,
20*x*N = z + N*y
Sub, 10x=y and (z=120y or 1200x), we get N = 120
Therefore, for 20 cows it takes 120 days to graze.
| Is This Answer Correct ? | 9 Yes | 0 No |
Answer / ayyangar
options are suspectable...
isn't it?
answer is 120
For 25 cows the days required are 80..
observe the equations
(40*x-g)*40=(30*x-g)*60=(20*x-g)*n.
where x is grass units per a cow,
g grass units incresed.
n is number of days reqired...
| Is This Answer Correct ? | 10 Yes | 3 No |
Answer / b.saravanan
answer is b)80 because the number of cows (20) which is
less than 30cows so obviously it will eat for more than 60
days
| Is This Answer Correct ? | 6 Yes | 3 No |
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