What are keywords in c with examples?

0 Answers  

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can u give me the good and very optimised code for a car racing game?

0 Answers  

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f1() { f(3);} f(int t) { switch(t); { case 2: c=3; case 3: c=4; case 4: c=5; case 5: c=6; default: c=0;} value of c?

5 Answers   Geometric Software,

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write a program for fibonaci series by using while loop in c?

2 Answers  

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please give me some tips for the placement in the TCS.

0 Answers   TCS,

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Write a program to add a given duration with time(24hrs format)

1 Answers   Protech,

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What is a keyword?

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What is an anonymous union and where to apply that ?

3 Answers   HP,

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what will the following program do? void main() { int i; char a[]="String"; char *p="New Sring"; char *Temp; Temp=a; a=malloc(strlen(p) + 1); strcpy(a,p); //Line no:9// p = malloc(strlen(Temp) + 1); strcpy(p,Temp); printf("(%s, %s)",a,p); free(p); free(a); } //Line no 15// a) Swap contents of p & a and print:(New string, string) b) Generate compilation error in line number 8 c) Generate compilation error in line number 5 d) Generate compilation error in line number 7 e) Generate compilation error in line number 1

1 Answers   IBM,

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in multiple branching construct "default" case is a) optional b) compulsarily c) it is not include in this construct d) none of the above

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I have an array of 100 elements. Each element contains some text. i want to: append a star character to the end of every fifth element remove every second character from every tenth element, and… add a line feed (ascii 10) after the 30th character of every array element whose length is greater than 30 characters.

1 Answers  

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18)struct base {int a,b; base(); int virtual function1(); } struct derv1:base{ int b,c,d; derv1() int virtual function1(); } struct derv2 : base {int a,e; } base::base() { a=2;b=3; } derv1::derv1(){ b=5; c=10;d=11;} base::function1() {return(100); } derv1::function1() { return(200); } main() base ba; derv1 d1,d2; printf("%d %d",d1.a,d1.b) o/p is a)a=2;b=3; b)a=3; b=2; c)a=5; b=10; d)none 19) for the above program answer the following q's main() base da; derv1 d1; derv2 d2; printf("%d %d %d",da.function1(),d1.function1(),d2.function1 ()); o/p is a)100,200,200; b)200,100,200; c)200,200,100; d)none 20)struct { int x; int y; }abc; you can not access x by the following 1)abc-->x; 2)abc[0]-->x; abc.x; (abc)-->x; a)1,2,3 b)2&3 c)1&2 d)1,3,4

1 Answers  

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