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Write a c program to print the even numbers followed by odd
numbers in an array without using additional array
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Answer / nitin garg
#include <stdio.h>
#include <conio.h>
#include <string.h>
int main()
{
int num[100],n,i,j;
printf("how many elements you enter
");
scanf("%d",&n);
printf("Enter %d elements
",n);
for(i=0;i<n;i++)
{
scanf("%d",&num[i]);
}
printf("
print the even numbers followed by odd
numbers
");
for(i=0;i<n;i++)
{
if(num[i]%2==0 && num[i+1]%2!=0)
printf("%d
",num[i]);
}
getch();
}
Output:
how many elements you enter
10
Enter 10 elements
2
4
6
8
10
12
14
16
18
19
print the even numbers followed by odd
numbers
18
| Is This Answer Correct ? | 0 Yes | 1 No |
You have given 2 array. You need to find whether they will create the same BST or not. For example: Array1:10 5 20 15 30 Array2:10 20 15 30 5 Result: True Array1:10 5 20 15 30 Array2:10 15 20 30 5 Result: False One Approach is Pretty Clear by creating BST O(nlogn) then checking two tree for identical O(N) overall O(nlogn) ..we need there exist O(N) Time & O(1) Space also without extra space .Algorithm ?? DevoCoder guest Posted 3 months ago # #define true 1 #define false 0 int check(int a1[],int a2[],int n1,int n2) { int i; //n1 size of array a1[] and n2 size of a2[] if(n1!=n2) return false; //n1 and n2 must be same for(i=0;i<n1-1;i++) { if( !( (a1[i]>a1[i+1]) && (a2[i]>a2[i+1]) ) ) return false; } return true;//assumed that each array doesn't contain duplicate elements in themshelves }
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