ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.29 : An engineering company that produces small biochemical tools applies Installment Sales Method in its accounting. Let A = Installment Sales, B = Cost of Installment Sales, C = Gross Profit, D = Gross Profit Ratio. In year 20X8, let A = $400, B = $250, C = $150. In year 20X9, let A = $450, B = $315, C = $135. If the value of D = 37.5 % in year 20X8 : (a) find the value of D for year 20X9; (b) calculate the realized gross profit = ED / 100, for year 20X8 when the cash collected from sales is E = $100.

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could anyone send me model question papers or outline of graduate trainee(chemical engg) post?

0 Answers   NPCIL,

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What are some typical applications for glass-lined reactors?

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What is the import procurement cycle? What are the customization steps in sap?

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what are the reaction between sodium meta bi sulphate and chlorine?

1 Answers   Dalkia,

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What is minimum flow required of NG having BTU value of 920 btu/scf for flame stability of LBTU gas of BTU value 220 BTU/SCF against the flow 80KPPH.

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what is R1,R2,R3, R4........?

0 Answers   Okaya,

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What industries require filtered compressed air?

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what is the apt definitions for apparent power ,active power and reactive power?and explanation about different types of lamps?

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What are some common methods for helium leak testing a vacuum system?

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POLYMER ENGINEERING - QUESTION 24.2 : Let C% be the fractional crystallinity, Rs = density of sample, Ra = density of amorphous form and Rc = density of crystalline form. In a polymer, these unknowns could be related by the equation C% = (Rc / Rs) (Rs - Ra) / (Rc - Ra). (a) Find the equation of Rc as a function of C%, Rs and Ra. (b) Two samples of a polymer, C and D exist. For sample C, C% = 0.513 when Rs = 2.215 unit. For sample D, C% = 0.742 when Rs = 2.144 unit. Both samples C and D have the same values of Ra and Rc. Find the values of Ra and Rc in 6 decimal places.

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Calculate the line size for a cooling water line with a volumetric flowrate of 1200m3/h of water. Density of water = 1000kg/m3

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