Answer / kms

The following code compares the strings alphabetically:

For example:

1. "bite" is greater than "apple" even though length of bite
is less than apple. ( it is greater lexicographically)

2. "It is good" is lower than "It is great".

CODE -->

#include<stdio.h>
#include<conio.h>

void strings_compare(char [], char []);

void main()
{
char str1[50], str2[50];
clrscr();
flushall();
printf("String 1 : ");
gets(str1);
flushall();
printf("String 2 : ");
gets(str2);
strings_compare(str1,str2);
getch();
}

void strings_compare(char str1[], char str2[])
{
int i=0,j=0,flag1=0,flag2=0;
printf("\nString 1 : ");
puts(str1);
printf("\nString 2 : ");
puts(str2);
printf("\n");
while(str1[i] != '\0' || str2[j] != '\0')
{
if(str1[i] < str2[j])
{
flag1 = 1;
break;
}
if(str1[i] > str2[j])
{
flag2 = 1;
break;
}
else
{
i++;
j++;
}
}

if(flag1==1)
{
printf("\n\ns1 : %s is lower than s2 : %s",str1,str2);
}
else if(flag2 == 1)
{
printf("\n\ns1 : %s is greater than s2 : %s",str1,str2);
}
else
{
printf("\n\nBoth strings are equal...");
}
}

Answer / md.ershad.ezaz

int strcompare(char *,char *);
void main()
{
char s1[15],s2[15];
int cmp;
clrscr();
puts("Enter first string");
gets(s1);
puts("Enter second string");
gets(s2);
cmp=strcompare(s1,s2);
if(cmp==0)
puts("strings are equal");
else
puts("strings are not equal");
getch();
}
int strcompare(char *p1,char *p2)
{
while(*p1==*p2)
{
if(*p1=='\0')
return(0);
p1++;
p2++;
}
return(*p1-*p2);
}

Answer / raj

#include<stdio.h>
void main()
{
char name[80],name1[80];
int i;
printf("enter 1st string");
gets(name);
printf("enter 2st string");
gets(name1);
i=0;
while(name[i]==name1[i] && name1[i]!='\0')
i++;
if(name[i]==name1[i])
printf("two strings r equal\n");
else
printf("two strings r not equal\n");
}

Answer / shashi

#include<stdio.h>
#include<conio.h>

int stringcmp(char s1[], char s2[]);

int main()
{

char str1[10],str2[10];

printf("\nEnter first String:");
scanf("%s",str1);

printf("\nEnter second String:");
scanf("%s",str2);


if (stringcmp(str1,str2))
{
printf("String s1:%s and s2:%s are EQUAL\n",str1,str2);
}
else
printf("String s1:%s and s2:%s are NOT EQUAL\n",str1,str2);
getch();

return 0;
}

int stringcmp(char *s1, char *s2)
{
int flag=0;
char *count;
count=s1;
while(*count++)
{
flag=0;
if(*s1++==*s2++)
{
flag=1;
}
}

return flag;

}

Answer / abhi

#include<stdio.h>
#include<conio.h>

main()
{
char *s1;
char *s2;

int flag=0;
s1=(char *)malloc(10);
s2=(char *)malloc(10);
scanf("%s",s1);
scanf("%s",s2);


while((*s1!='\0')||(*s2!='\0'))
{
if(*s1!=*s2)
flag=1;
else
{
s1++;
s2++;
}
if(flag)
{
if(*s1<*s2)
flag=-1;
break;
}}

if(*s1=='\0'&&*s2!='\0')
flag=-1;
else if(*s1!='\0'&&*s2=='\0')
flag=1;
else
{}
printf("%d",flag);


getch();
}

Answer / navy

#include<stdio.h>
#include<conio.h>
void main()
{
char s1[20];
int i, j, len=0, flag=0;
printf("\nEnter any string: ");
gets(s1);
for (i=0; s1[i]!='\0'; i++)
len++;
i = 0;
j = len-1;
while (i < len)
{
if (s1[i] != s1[j])
{
flag = 1;
break;
}
i++;
j--;
}
if (flag == 0)
printf("\nString is palindrome");
else
printf("\nString is not palindrome");
getch();
}

Answer / sujith

#include<stdio.h>
int str_cmp(const char *s1, const char *s2)
{
unsigned int i = 0, diff;
while(*(s1+i) && *(s2+i))
{
diff = (*(s1+i)-*(s2+i));
if(!diff)i++;
else break;
}
return diff;
}
int main()
{
printf("chuma %d ", str_cmp("abcd","abcde"));
return 0;
}
U can use this as a prototype and enhance this. I havent
even tried compilng this.
Sujith

Answer / fionaa

corrected:

Returns an integral value indicating the relationship
between the strings:
A zero value indicates that both strings are equal.
A value greater than zero indicates that the first character
that does not match has a greater value in str1 than in
str2; And a value less than zero indicates the opposite.

int compare(char str1[], char str2[]) {
int flag = -1;
int i=0;
while(str1[i]!='\0' && str2[i]!='\0'){
if((str1[i]==str2[i])) {flag = 0;}
else if (str1[i]>str2[i]) {
flag=1;
break;
}else if(str1[i]<str2[i]){
flag = -1;
break;
}
i++;
}

if(strlen(str1)==strlen(str2) && flag==0 ){
flag = 0;
}
else if(strlen(str1)>strlen(str2) && flag==0 ){
flag = 1;
}
else if(strlen(str1)<strlen(str2) && flag==0 ){flag = -1;}
return flag;

}

Answer / anil sai krishna

#include<stdio.h>
main()
{
char a[15],b[15];
int i,l=0,m;
printf("enter the two strings");
scanf("%s%s",a,b);
for(i=0;a[i]=b[i];i++)
{
l++;
}
for(i=0;a[i]!='\0';i++)
{
m++;
}
if(l==m)
{
printf("strings are equal");
}
else
{
printf("not equal");
}
}

Answer / shashank kapoor

//PROGRAM TO COMPARE TWO STRINGS
#include<iostream.h>
#include<conio.h>
#include<string.h>
void main()
{
char str[10],ptr[10];
int 1,flag,a,b,x,y;
cout<<"Enter two strings:"<<endl;
cin>>str;
a=strlen(str);
cin>>ptr;
b=strlen(ptr);
for(i=0;i<(a>b?a:b);i++)
{
if(str[i]>ptr[i])
{
x=str[i]-ptr[i];
flag=1;
}
else if(str[i]<ptr[i])
{
y=str[i]-ptr[i];
flag=2;
}
}
if(flag==1)
cout<<"Str is greater than Ptr by: "<<x;
else if(flag==2)
cout<<"Str is smaller than Ptr by: "<,y;
else
cout<<"Str & Ptr are EQUAL";
getch();
}

Explain what are compound statements?

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