what is out put of the following code?
#include
class Base
{
Base()
{
cout<<"constructor base";
}
~Base()
{
cout<<"destructor base";
}
}
class Derived:public Base
{
Derived()
{
cout<<"constructor derived";
}
~Derived()
{
cout<<"destructor derived";
}
}
void main()
{
Base *var=new Derived();
delete var;
}
- 3 Answers
- 7044 Views
- Honeywell, I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / pooja sonawane
error.
because, there is no header file.
and no ";" is given after the end of classes.
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / kapil
There are 3 errors mainly
first header files are not included
second no semicolon at the end of class
third constructor of class cannot be private
if all these three errors are removed the output will be
constructor base
constructor derived
destructor base
| Is This Answer Correct ? | 1 Yes | 0 No |
the question is that what you have been doing all these periods (one year gap)
How does free() know how many bytes to free?
What do you mean by dynamic memory allocation in c?
What is the difference between getch() and getche()?
write a program for fibonaci series by using while loop in c?
What is the c language function prototype?
define switch statement?
What is a good way to implement complex numbers in c?
If a variable is a pointer to a structure, then which operator is used to access data members of the structure through the pointer variable?
Write a c program using for loop in switch case?
write a program to concatenation the string using switch case?
Explain the use of #pragma exit?
C 
