what is out put of the following code? #include class Base { Base() { cou

what is out put of the following code?
#include
class Base
{
Base()
{
cout<<"constructor base";
}
~Base()
{
cout<<"destructor base";
}
}
class Derived:public Base
{
Derived()
{
cout<<"constructor derived";
}
~Derived()
{
cout<<"destructor derived";
}
}
void main()
{
Base *var=new Derived();
delete var;
}

Question Posted / nazim

3 Answers
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what is out put of the following code? #include class Base { Base() { cout<<"const..

Answer / pooja sonawane

error.
because, there is no header file.
and no ";" is given after the end of classes.

Is This Answer Correct ?

2 Yes

1 No

what is out put of the following code? #include class Base { Base() { cout<<"const..

Answer / kapil

There are 3 errors mainly
first header files are not included
second no semicolon at the end of class
third constructor of class cannot be private

if all these three errors are removed the output will be
constructor base
constructor derived
destructor base

Is This Answer Correct ?

1 Yes

0 No

what is out put of the following code? #include class Base { Base() { cout<<"const..

Answer / anvesh

there is no include file iostream for cout
immproper ending for classes ';'

Is This Answer Correct ?

0 Yes

0 No

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