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A and B combinely can do a work in 4 days. If A alone can
do a piece of work 6 days. In how many days B alone can do?
a) 8 days b) 6 days c)10 days d) 12 days
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Answer / geetika thakkar
say the work is w and let no of days taken by b is 'x' which
we have to calculate
so work done by a in one day is w/6
work done by b in one day is w/x
a and b together can do work in 4 days ie=(w/6)+(w/x)=(w/4)
solving equation x=12
so no of days taken by b=12
| Is This Answer Correct ? | 9 Yes | 1 No |
Answer / tam
combinely job=A+B=4days
when A is alone job=A=2
then B=4-A
=4-2
B=2
so,the ans is b
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / tam
sorry i have posted a wrong method,
A+B=4
then Ais equal to B,ie,A=B=2
so,
if Acan do the work in 6 days then B also can do the work
with in 6 days.
now the ans is b.
| Is This Answer Correct ? | 3 Yes | 2 No |
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