what will be the output:
main(){char ch;int a=10;printf("%d",ch);}
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Answer / vignesh1988i
garbage ascii value corresponding to the characterr present
in the memory location ch;
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / manjot singh
It will gve a garbage value becoz ch has not value it will
automtically generate value by complier
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / amala v
It'll give a warning tat "a is never used...If u Continue
executing...it will the memory address that is currently
used.
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / lnk
In the above coding ...
there is a char "ch " assigned with out a value
and a int" a " assigned with a value ...
and it compiles to print a interger (%d) ...
but tries to read a int value fronm ch (which does not
match the data type ) so it gives garbage value .with
compile time warning !
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / kalpana.y
There will be no output
because,in printf statement the integer variable is
declared but 'ch' is assinged.it should be 'a' insted
of 'ch'.
| Is This Answer Correct ? | 5 Yes | 5 No |
Answer / raghu
I think it prints some garbage value. if ch was initialised
then it would have printed the ASCII value of that charecter
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / balaji
warning! "a" is assigned a value that is never used
| Is This Answer Correct ? | 0 Yes | 0 No |
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