Answer / kangchuentat

ENGINEERING DRAWING - ANSWER 18.3 : (a) s = 3.142 d, then d = s / 3.142 = 3 / 3.142 = 0.9548 metres. Since 10 units : 10 metres, then d = 0.9548 units. (b) 1 unit : 1 metre or 1 centimetre : 1 metre for engineering drawing : actual object, then 0.01 m : 1 m or 1 : 100 is the scale used. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

I HAVE BEEN SELECTED FOR IOCL PANIPAT INTERVIEW,ACCTUALLY IAM DOING APPRENTIES TRAINEE IN CPCL.IAM GOING TO ATTEND THE IOCL PANIPAT INTERVIEW.SO PLEASE HELP ME HOW I PREPARE FOR INTERVIEW BY SUBJECT AND ALSO BY FIELD.

0 Answers   IOCL,

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Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt % methanol and the second contains 70.0 wt % methanol. If 200 kg of the first mixture is combined with 150 kg of the second, what are the mass and composition of the product? The symbol of weight percent is wt %.

2 Answers  

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any meter avilable for measureing the Transformer Losses. ( like Voltmeter for voltage & ammiter for currenr )if yes plz give the make & supplier address, Email, Phone number.

0 Answers   Piramal Healthcare,

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how much height hight work permit requred

2 Answers   Atul, BARC,

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Why chlorine cylinders are laid down horizontally?

3 Answers  

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Are carbon steel storage tanks appropriate for NaOH solutions?

1 Answers  

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What is the difference between multi grade filter and dual media filter?

1 Answers   Dalkia, Oil and Gas Jobs,

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ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.19 : In the purchase of a unit of engineering office, a loan has been made to a bank with the following details : Term N = 30 years; interest rate R = 8.07 % / year; security : primary residence; present value pv = $450000; salary = $75000 / year or $56000 / year after tax. (a) Let the discounted present value PV = [ 1 - 1 / (1 + r) ^ n ] / r for arrears, where r = interest rate of discount, n = number of payment, ^ = symbol for power. If the loan repayment was made monthly : (i) calculate the value of r where r = R / k and R is in decimal value; (ii) find the value of n where n = kN; (iii) estimate the value of k where k = number of repayment per year; (iv) calculate the value of PV based on the formula of discounted present value. (b) Calculate the monthly repayment of the loan, MR based on the following formula : pv = PV x MR. (c) Find the percentage of salary remains after paying the loan every month.

1 Answers  

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Question - Chemical Engineering Material - In crystal material, hexagonal crystal system could form 4-digit index in certain direction of solid. For [1(-1)0] direction in the hexagonal crystal systems of particular catalyst applied in fume removal of incinerator, what is the four-digit index for this direction? Hint : The transformation equations between the 3-digit [h’k’l’] and the 4-digit [hkil] indices are : h = (1/3) (2h’ – k’); i = - (h + k); k = (1/3) (2k’ – h’); l = l’. A. [(-1)100] B. [1(-1)00] C. [(-1)000] D. [00(-1)(-1)] E. [(-1)0(-1)0]

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PETROLEUM ENGINEERING - QUESTION 25.3 : Liquid octane has a density of 703 kilograms per cubic metre and molar mass of 114.23 grams per mole. Its specific heat capacity is 255.68 J / (mol K). (a) Find the energy in J needed to increase the temperature of 1 cubic metre of octane for 1 Kelvin. (b) At 20 degree Celsius, the solubility of liquid octane in water is 0.007 mg / L as stated in a handbook. For a mixture of 1 L of liquid octane and 1 L of water, prove by calculations that liquid octane is almost insoluble in water.

1 Answers  

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Should slurry pipes be sloped during horizontal runs?

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ENGINEERING MATERIAL - EXAMPLE 12.3 : Let a ^ 2 = a x a and a ^ 3 = a x a x a where ^ is power function. Niobium is a metal with a body-centered cubic structure. The length of the unit cell structure is b = 0.3349 nm. (a) Find the volume for a unit cell structure for niobium. (b) There are 2 atoms per unit cell structure of niobium. The metal has a molar mass of 92.9 g / mol. One mole of the metal consists of 6.02 x 10 ^ 23 atoms. Find the mass of niobium per unit cell and the density of niobium.

1 Answers  

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