Question 106 - In a wavefunction, let P(x) = A cos kx + B sin kx. By using the

Question 106 - In a wavefunction, let P(x) = A cos kx + B sin kx. By using the boundary conditions of x = 0 and x = l, where P(0) = P(l) = 0, prove by mathematical calculation that P(x) = B sin (npx / l) where p = 22 / 7 approximately, n is a rounded number. A, B and k are constants.

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Question 106 - In a wavefunction, let P(x) = A cos kx + B sin kx. By using the boundary conditions ..

Answer / kangchuentat

Answer 106 - When x = 0, P(0) = A cos (k x 0) + B sin (k x 0) = A = 0. When x = l, P(l) = A cos (k x l) + B sin (k x l) = 0 = B sin (k x l), then k x l = arc sin 0 = np, k = np / l. Finally P(x) = B sin kx = B sin (npx / l) as proven. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

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