How would you delete observations with duplicate keys?
Answers were Sorted based on User's Feedback
Answer / mohan reddy
proc sort data=work.abc nodupkey;
by eno;
run;
when u have delete duplicatie obervation from dataset. u can
use the nodupkey along with the by variable.
Is This Answer Correct ? | 10 Yes | 0 No |
Answer / g.jyotshna
proc sort data=datasetname nodup;
by var;
run;
proc sort data=datasetname nodupkey;
by var;
run;
proc sort data=datasetname noduprecs;
by var;
run;
Is This Answer Correct ? | 4 Yes | 0 No |
Answer / rohit
You can also use a Proc SQL statement with a Distinct
keyword.
Proc Sql;
Select Distinct tablename.* from tablename;
Quit;
Is This Answer Correct ? | 3 Yes | 0 No |
Answer / upendra
Data <datasetname>;
Set <datasetname>;
by <var>;
If last.var;
run;
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / siddu
proc sort data=<master dataset> out=(newdata set name>
nodup key;
by <key variable>;
run;
Is This Answer Correct ? | 0 Yes | 1 No |
Intern stastical programmer written test
There are 200 observations in a dataset, i want to pull out the observation no's 100, 150,180,190 by using Proc SQL? How you can get it?
Have you ever used the SAS Debugger?
/* This is example of age caluculate wihtout to display perfect days and years in output window */ data age; retain dob "12jun2003"d now "24may2011"d; age1=now-dob; age=(now-dob)/365.25; years=int(age); days1=round((age-years)*365.25); months=month(now)-1; if days1 gt 30 and months in(12,10,8,6,4,2)then do; month1=days1/30.4375; month=int(days1/30.4375); if day(now)=1 then days=1; else days=round((month1-month)*30.4375)+1; drop days1 month1 month; end; else if days1 gt 30 and months in (1,3,5,7,9,11)then do; month1=days1/30.4375; month=int(days1/30.4375); if day(now)=1 then days=1; else days=round((month1-month) *30.4375); drop days1 month1 month; end; drop age age1; proc print data=age; format dob now date.; run;
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