Answer / dinesh

DECLARE
c date:='01-JAN-15';
d date:='31-DEC-15';
a number(10);
BEGIN
a:=d-c;
FOR i in 1..a
LOOP
IF to_char(c,'DY')='FRI' THEN
DBMS_OUTPUT.PUT_LINE('THIS IS FRIDAY DATE:='|| ' '|| c);
END IF;
c:=c+1;
END loop;
END;

Answer / dinesh

CREATE OR REPLACE PROCEDURE display_day_date(c date,d date,v varchar2) IS
a number(10);
m date:=c;
BEGIN
a:=d-m;
FOR i in 1..a
LOOP
IF to_char(m,'DY')= v THEN
DBMS_OUTPUT.PUT_LINE('THIS IS'||' '|| v ||' ' || 'DATE for the year '||' '||to_char(m,'yyyy')|| ' '|| m);
END IF;
m:=m+1;
END loop;
END;

Answer / nihar meher

declare
a date;
b date;
c number(15);
begin
select trunc(sysdate,'yyyy') into a from dual;
select add_months(trunc(sysdate,'yyyy'),12)-1 into b from dual;
c:=b-a;
for i in 1..c
loop
if to_char(a,'dy')='fri'
then
dbms_output.put_line(a);
end if;
a:=a+1;
end loop;
end;

Answer / kuldeep

select * from
(

SELECT (TRUNC (SYSDATE, 'yyyy') + LEVEL - 1) dt,
TRIM(TO_CHAR ((TRUNC (SYSDATE, 'yyyy') + LEVEL - 1), 'Day')) dy
FROM DUAL
CONNECT BY LEVEL <= 365

)
where dy='Friday'

C. Normalize the following data up to the 3rd Normal form. Create the tables and insert the data given. Emp_ID Name Dept_Name Salary Course_Title Date_Completed 100 Adam Marketing 48,000 SPSS 6/19/2008 Surveys 10/7/2008 140 Bob Accounting 52,000 Tax Acc 12/8/2008 110 Cathy IT SQL Server 1/12/2008 C# 4/22/2008 190 Dan Finance 150 Emily Marketing 55,000 SPSS 6/16/2008 42,000 Analysis 8/12/2008 Queries 1. Find all Names who have completed the SPSS Course. 2. Find employee with max salary. 3. Find employee with 2nd max salary. 4. Find all employees in Dept “Marketing”. 5. Find all the employees who have taken more than 2 courses. 6. Find all the employees who have completed the courses before month of September.

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