how to find nth highest salary
Answers were Sorted based on User's Feedback
Answer / rahul tripathi
The Genral answer which can work on any SQL:-
select salary from emp e1 where (n-1)=(select count(*)
from emp where salary > e1.salary )
Rahul Tripathi
rahultripathi@inkanpur.com
| Is This Answer Correct ? | 249 Yes | 76 No |
Answer / brahma
select * from table_name t1 where (n-1)=
(select count(distinct(column_name)) from table_name t2
where t2.column_name>t1.column_name)
| Is This Answer Correct ? | 101 Yes | 47 No |
Answer / kavitha.r
Sorry. This one is correct
select top 1 salary from employee where salary in (select
distinct
top n salary from employee order by salary desc) order by
salary asc
| Is This Answer Correct ? | 44 Yes | 18 No |
select * from tablename.aliasname where nth=select
count(sal) from tablename where aliasname.sal<=sal
| Is This Answer Correct ? | 38 Yes | 26 No |
Answer / nidhish
replace the N with wat ever number u want
select min(salary) from employee where salary in ( select
distinct top N salary from employee order by salary desc)
| Is This Answer Correct ? | 26 Yes | 17 No |
Answer / amit
select * from emp as e1 where sal (n-1) = select distinct
(count(*) from emp as e2 where e2.sal>e1.sal)
Where n is no that u want which postion's salary u want
suppose second higest means n=2
Amit
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / ayush sharma
select sal from (select distinct sal from emp order by desc)
where rownum <=n minus select sal from(select distinct sal
from emp order by desc) where rownum<=n-1;
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / ramakrishna
select e1.* from emp e1 where n=(select
count(distinct(e2.sal)) from emp e2 where e1.sal<=e2.sal);
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / bharath
select distinct(sal) from emp a where 3 = (select
count(distinct(sal)) from emp b where a.sal<= b.sal)
replace 3 by 2 for second highest...
| Is This Answer Correct ? | 4 Yes | 0 No |
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