Consider the following algorithm:
for ( i = 2 ; i <= n ; i++) {
for ( j = 0 ; j <= n) {
cout << i << j ;
j = j + floor(n/4) ;
}
}
(a) What is the output when n = 4
(b) What is the time complexity T(n). You may assume that n is divisible 4.
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Consider the following algorithm: for ( i = 2 ; i <= n ; i++) { for ( j = 0 ; j <= n) { cout << i << j ; j = j + floor(n/4) ; } } (a) What is the output when n = 4 (b) What is the time complexity T(n). You may assume that n is divisible 4.
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