Answer / sujit pingale

Ans: select distinct(a.salary) from customers a where &n =
(select count(distinct(b.salary)) from customers b where
a.salary <= b.salary);

It will ask you to enter number in input box which salary
you want to see

Answer / sujitpingale

Ans: select distinct(a.salary) from customers a where &n =
(select count(distinct(b.salary)) from customers b where
a.salary <= b.salary);

Enter value in inputbox. If you enter 1 then it will give
highest salary

Answer / ajit

select e.*, rn
from ( select empno, ename, sal, deptno, dense_rank() over ( order by sal desc ) rn
from emp) e
where rn = & rn;

Answer / abhishekjaiswal

SELECT A.FIRST_NAME,
       A.SALARY
   FROM EMPLOYEES A
   WHERE 3 = ( SELECT COUNT(*) -- Replace 3 with any value of (N - 1)
               FROM EMPLOYEES B
               WHERE B.SALARY > A.SALARY)

Answer / pavan

select e.* from emp e where &n=(select count(distinct e1.sal)from emp e1 where e.sal>e1.sal)

Answer / ajit

select *
from emp
where sal = ( select max(sal)
from emp
where level = &n
connect by prior sal > sal
group by level);

what is the main difference between join and subqurey?

3 Answers   Oracle,

Table1: Col1 col2 1 2 10 3 4 89 5 6 Table:2 Col1 col2 3 2 9 5 4 7 6 87 With the help of table1 and table2 write a query to simulate the fallowing results. Output1: Col1 col2 1 2 2 3 3 4 4 5 5 6 Output2: Col1 col2 2 3 10 4 5 89 6 7 1.Write query for single row to multiple row using sql statements. Eg:a,b,c,d,e,f Change to A B C D E F 2. Write query for multiple row to single row using sql statements. Eg2 A B C D E F Change to Eg:a,b,c,d,e,f Table1: Col1 col2 8 5 2 9 4 2 5 1.Write a query to select all the rows from a table1,if the value of A is null then corresponding B’s value should be printed in A’s value.if the value of A is null in that table then corresponding B’s value should be printed as 30. 2. write a query to find the sum of A and B .display the max among both. 3.write a query to find total number of rows from table 1. Note: if any column value is null in a row then that row should be considered as 2 rows. 4.write a query to display all the records of table1 except A containg 2 as well B containg 5. 5.rewrite the fallowing without using join and group by. Select b.title,max(bc.returneddate –bc.checkoutdate)” mostdaysout” From bookshelf_checkout bc, Book shelf B Where bc.title(+)=b.title Group by b.title. 6.rewrite fallowing query Select id_category from category_master X where exists (select 1 from sub_category Y where X.id_category=Y.id_category) Customer: Name phone1 phone2 phone3 bitwise A 23456 67890 12345 --- B 67459 89760 37689 --- Don’t_call Col1 67890 37689 1.q) update the customer table of bitwise with 1 or 0. Exists in don’t_call table menas show -1 Other wise -0. Output. Name bitwise A 010 B 010

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