Answer / v venu gopal

A won 3 games 18 rupees over all he lost 9 rupees so, 12
games they played

Answer / harini

6games

Answer / devi

Total games Played - 14
A wins - 3
B wins 5 (5*6-9*3=30-27=3rs)
C wins 6 (6*6-8*3 = 36-24= 12rs)

Answer / ramesh

5

Answer / yuhaa

9 games

Answer / vetri

5

Answer / himanshu

10 games

Answer / sachin punjabi

let
no of games won by A =x
no of games won by A =y
no of games won by A =z
a won 3 games. so x=3;
the equations which are formed are
6y - 3z- 3x = 12
6z - 3y- 3x = -3
so putting 3x=9.
2y - z =7
2z - y =2
y = 16/3 WHICH IS NOT POSSIBLE !!!!
SO THEY WILL NOT GET THAT SCORE !!EVEN IF THEY PLAY FOR
ETERNITY!!!

Answer / sarat

8 games They played
A own 3 games = 18 Rs
B loss 3 Rs and own 1 games i,e 9(A own 3 Games)-6(B own
1 game)=3

c own 12 Rs and loss 4 games(A own 3+b own 1) and own 4
games i.e 24(own)-12(loss)

so totally A own 3 games
B own 1 game
c own 4 games
=8

Answer / siya

3

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