Answer / amiricks

Hi Nitin concept is correct but above code is not working fine
as it shows only not a palindrome....

here i have written one simple code any suggestions are most
welcome

val = Inputbox("Enter any string")
L= LEN(val)
for i = L to 1 step -1
v= mid(val,i,1)
va = va&v
Next
if val= va then
msgbox "Name is a Palindrome"
Else
Msgbox "Not a palindrome"
End if


Regards
Amit
umesh.amitkumar@gmail.com

Answer / nitin jagjivan

Strng = "NITIN"
temp = "Pass"
dim arr()

Strng_Length = len(Strng)
redim arr(Strng_Length)

For i=1 to Strng_Length
arr(i-1)= mid(Strng,i,1)
Next

For i=1 to round(Strng_Length/2)
If instr(ucase(arr(i-1)),arr(Strng_Length-
i)) = 0 then
temp = "Fail"
End If
Next

If temp <> "Fail" then
msgbox "Given input is a palindrome"
Else
msgbox "Try another String, Not Pali"
End If

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