Answer / chetan

A beats b by 10m in a 100m race
I.e a=100m b=90m
B beats c by 20m
I.e b=100m c=80m
Now when b was= 90m, c was=?
But wen b was=100m, c was=80
90*80/100 =72 (cross multiply)
So when A was 100m , b was 90m, c was 72m
Therfore. Distance between a and c is 100-72=28m

Answer / avcs

The answer is 28m.
Let A completes race in t1 secs.
velocity(A)=100/t1 ; Velocity (B)=90/t1;

B completes race in t2 secs
Velocity(B)=100/t2; Velocity (C)=80/t2;

now 90/t1=100/t2 => t2=10*(t1)/9;

Velocity (C) = 80 * 9/10*(t1)= 72/t1;

So A defeats C by 28 meters.

Answer / anurag gour

Let Speed of A be 10m/s. Therefore, accordingly speed of B will be 9m/s.

Now time taken by B to complete the race of 100m will be:
=>100/9=11.1sec

Now in 11.1sec C has covered 80m as C is defeated by 20m.
Speed of C=80/11.1 = 7.207m/s.

Since A has covered his race in 10sec(100m/10m/s). Therefore distance covered by C in 10 sec = 7.207x10 = 72.07m or 72m.

So, A defeats C by 100-72=28m.

Answer is 28m.

Answer / rahul

28

Answer / amit rajak

According to Question

let

A has covered 100 metres when B is at 90 metres
and B defeated c by 20 metres so if we subtract 90-20

answer will be 70m
means when A is at 100m

C was at 70 metres so

the distance BETWEEN A & B
and answer is 30 metres

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